Science:Math Exam Resources/Courses/MATH152/April 2011/Question A 12

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MATH152 April 2011

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Question A 12
Write the matrix of the rotation which transforms $\left[{\begin{array}{c}0\\1\end{array}}\right]$ to $\left[{\begin{array}{c}-1\\0\end{array}}\right].$

Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?

If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint.

Hint 1
Either try drawing a picture or try setting up an arbitrary matrix and solving the resulting system of equations.

Hint 2
Rotation matrices have the form $\left[{\begin{array}{c c}\cos(\theta )&-\sin(\theta )\\\sin(\theta )&\cos(\theta )\end{array}}\right]$

Checking a solution serves two purposes: helping you if, after having used all the hints, you still are stuck on the problem; or if you have solved the problem and would like to check your work. If you are stuck on a problem: Read the solution slowly and as soon as you feel you could finish the problem on your own, hide it and work on the problem. Come back later to the solution if you are stuck or if you want to check your work. If you want to check your work: Don't only focus on the answer, problems are mostly marked for the work you do, make sure you understand all the steps that were required to complete the problem and see if you made mistakes or forgot some aspects. Your goal is to check that your mental process was correct, not only the result.

Solution 1

As rotation matrices are of the form $\left[{\begin{array}{c c}\cos(\theta )&-\sin(\theta )\\\sin(\theta )&\cos(\theta )\end{array}}\right]$ We must have that $\left[{\begin{array}{c c}\cos(\theta )&-\sin(\theta )\\\sin(\theta )&\cos(\theta )\end{array}}\right]\left[{\begin{array}{c}0\\1\end{array}}\right]=\left[{\begin{array}{c}-1\\0\end{array}}\right]$ This gives us that $\left[{\begin{array}{c}-\sin(\theta )\\\cos(\theta )\end{array}}\right]=\left[{\begin{array}{c}-1\\0\end{array}}\right]$ or more simply $\displaystyle -\sin(\theta )=-1$ and $\displaystyle \cos(\theta )=0$ Thus, we plug in these values into our matrix and we see that $\left[{\begin{array}{c c}\cos(\theta )&-\sin(\theta )\\\sin(\theta )&\cos(\theta )\end{array}}\right]=\left[{\begin{array}{c c}0&-1\\1&0\end{array}}\right]$ will do the trick.

Solution 2

As rotation matrices have the form $\left[{\begin{array}{c c}\cos(\theta )&-\sin(\theta )\\\sin(\theta )&\cos(\theta )\end{array}}\right]$ and a diagram shows that we are rotating the first vector (which is a unit vector on the positive y-axis) a total of ${\frac {\pi }{2}}$, we have that the rotation matrix that solves our problem is $\left[{\begin{array}{c c}\cos({\tfrac {\pi }{2}})&-\sin({\tfrac {\pi }{2}})\\\sin({\tfrac {\pi }{2}})&\cos({\tfrac {\pi }{2}})\end{array}}\right]=\left[{\begin{array}{c c}0&-1\\1&0\end{array}}\right]$

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