Science:Math Exam Resources/Courses/MATH103/April 2012/Question 02 (c)
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Question 02 (c) 

Short answer question. Simplify your answer to the best possible. Show in detail how you arrive at your answer (work will be considered for this problem). Find the center of mass of the distribution 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! 
Hint 

The centre of mass of the shape delimited by the xaxis, the vertical lines x = a, x = b and the curve y = ƒ(x) is given by 
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Solution 

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Please rate my easiness! It's quick and helps everyone guide their studies. The centre of mass is given by where We start with the simpler integral M and use the substitution w = x/2. Then dw = dx/2, or equivalently, dx = 2dw. Further, when x = π we have w = π/2 and when x = 0 we have w = 0. The integral M therefore becomes Next we calculate I. This is done using integration by parts: Choose u = x and . Then du = dx and from the integral we just solve, we know that . Hence For the second integral we again used our favourite substitution w = x/2. The center of mass is thus 