Science:Math Exam Resources/Courses/MATH110/April 2012/Question 04
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Question 04 

Write down a piecewise algebraic expression for a function ƒ satisfying all of the following criteria.
Make a large sketch of the graph of ƒ as well. 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! 
Hint 

Try drawing a graph satisfying the first criterion and then modifying it to also satisfy the next criterion, and so on until you've used all four criteria. 
Checking a solution serves two purposes: helping you if, after having used the hint, you still are stuck on the problem; or if you have solved the problem and would like to check your work.

Solution 

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Please rate my easiness! It's quick and helps everyone guide their studies. As was suggested in the hint, one way to approach this problem is to draw a function that satisfies the first criterion and then modify it to fit each following criterion. It is worth noting that there are many, many ways to draw a picture satisfying all 4 criteria  the solution that follows is just one example. Our first criterion is that the function be defined on the interval [1,1]. We will draw just a straight line at on this interval: Now we add the criterion that the function be discontinuous at and . One simple way to do this (without making the function undefined at those points, remember part 1!) is to move the two points at and to a new location, in our case, the xaxis. Now we want to have a global minimum at . This is easy enough  we'll just move our point that's now at the origin down until it is the lowest point on the entire graph. Finally, we can't have a local or global maximum. Right now, our straight line is both a local and global maximum because each point on the line is greater than or equal to its neighboring points. In order to make sure that each point on our line has a neighbor that is greater than itself, we will tilt the line, like so: There are two important things to note here: first, this change has not altered any of the previous criteria (still defined on [1,1], still discontinuous at appropriate points, etc.) Second, look at the right endpoint of the graph. Because this point is undefined, cannot have a global or local maximum at this point, and any point on the line cannot be a maximum either. Thus we have drawn a function that satisfies all four criteria. We now simply translate our picture into a piecewise function. The "line" will be two pieces, and each point at and will be another piece each.
