MATH101 April 2005
• Q1 (a) • Q1 (b) • Q1 (c) • Q1 (d) • Q1 (e) • Q1 (f) • Q1 (g) • Q2 (a) • Q2 (b) • Q2 (c) • Q2 (d) • Q3 (a) • Q3 (b) • Q3 (c) • Q4 • Q5 (a) • Q5 (b) • Q6 (a) • Q6 (b) • Q7 (a) • Q7 (b) • Q7 (c) • Q8 (a) • Q8 (b) •
Question 01 (d)
Find the general solution of the differential equation
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?
If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it!
This is a 2nd order differential equation with constant coefficients. So, you can begin by assuming that the general solution is the sum of two exponential functions, each of the form , where is a constant.
(Remember that there are special cases where solutions of the differential equation may look like sines and cosines, or may include a linear term in front of the exponential term.)
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This is a 2nd-order differential equation with constant coefficients. So make the substitution of into the equation and solve for .
Solving for we find that there is a double root . Thus we have found that one solution is , but we need to find a second solution. We multiply the first solution by and confirm that it is indeed a solution of the above equation (i.e: Let be another possible solution and substitute it into the differential equation).
Thus, the general solution is
where are arbitrary constants.
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MER QGH flag, MER QGQ flag, MER QGS flag, MER RT flag, MER Tag Differential equation (higher order)