Science:Math Exam Resources/Courses/MATH312/December 2008/Question 05 (a)

MATH312 December 2008

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[hide] Question 05 (a)

Alice wants Bob to send her a secret integer P between 0 and 1250 using RSA encryption with key $\displaystyle (e,n)=(1189,1271)$ (so the exponent is 1189 and the modulus is 1271, it is way too small to be really secure, but basic RSA encryption and decryption methods still work of course). (a) Bob knows that (the plaintext) $\displaystyle P=101$, he computes the ciphertext $\displaystyle C=35$ and communicates this number to Alice. Explain how Bob computed C.

Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?

If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it!

[show] Hint
No hint here. Review your notes for the RSA protocol (or check out the Wikipedia page).

Checking a solution serves two purposes: helping you if, after having used the hint, you still are stuck on the problem; or if you have solved the problem and would like to check your work. If you are stuck on a problem: Read the solution slowly and as soon as you feel you could finish the problem on your own, hide it and work on the problem. Come back later to the solution if you are stuck or if you want to check your work. If you want to check your work: Don't only focus on the answer, problems are mostly marked for the work you do, make sure you understand all the steps that were required to complete the problem and see if you made mistakes or forgot some aspects. Your goal is to check that your mental process was correct, not only the result.

[show] Solution
To compute the ciphertext given the plain text, one must compute $\displaystyle P^{e}\mod {n}$ and in this case, we have $\displaystyle 101^{1189}\equiv 35\mod {1271}$ so the value of the ciphertext is $\displaystyle C=35$. Note: You do not need to actually perform the above computation. It is given to us.

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