Science:Math Exam Resources/Courses/MATH307/December 2012/Question 04 (b)

MATH307 December 2012

Work in progress: this question page is incomplete, there might be mistakes in the material you are seeing here.

  •  Q1 (a)  •  Q1 (b)  •  Q1 (c)  •  Q1 (d)  •  Q1 (e)  •  Q2 (a)  •  Q2 (b)  •  Q3 (a)  •  Q3 (b)  •  Q3 (c)  •  Q3 (d)  •  Q3 (e)  •  Q4 (a)  •  Q4 (b)  •  Q4 (c)  •  Q4 (d)  •  Q4 (e)  •  Q5 (a)  •  Q5 (b)  •  Q5 (c)  •  Q5 (d)  •  Q6 (a)  •  Q6 (b)  •  Q6 (c)  •  Q6 (d)  •  Q6 (e)  •  Q6 (f)  •  

   Other MATH307 Exams

  •  December 2012  •  April 2013  •  April 2012  •  April 2006  •  December 2008  •  December 2010  •  

Question 04 (b)
Consider the Fourier series $t^{2}-t=\sum _{n=-\infty }^{\infty }c_{n}e^{2\pi int}$ for $0\leq t\leq 1$. (b) The coefficient cn can be written as an inner product $c_{n}=\langle f,g\rangle$. What are ƒ and g?

Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?

If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it!

Hint

Checking a solution serves two purposes: helping you if, after having used the hint, you still are stuck on the problem; or if you have solved the problem and would like to check your work. If you are stuck on a problem: Read the solution slowly and as soon as you feel you could finish the problem on your own, hide it and work on the problem. Come back later to the solution if you are stuck or if you want to check your work. If you want to check your work: Don't only focus on the answer, problems are mostly marked for the work you do, make sure you understand all the steps that were required to complete the problem and see if you made mistakes or forgot some aspects. Your goal is to check that your mental process was correct, not only the result.

Solution

Found a typo? Is this solution unclear? Let us know here. Please rate my easiness! It's quick and helps everyone guide their studies. To compute the coefficient, start with $f(t)=\sum _{n=-\infty }^{\infty }c_{n}e_{n}(t)$ where $\displaystyle f(t)=t^{2}-t$ and $\displaystyle e_{n}(t)=e^{2\pi int}$. Also, we have L=1-0=1. Take the inner product of ƒ(t) with $e_{m}$. The only term in the infinite sum that remains is the one with $n=m$, and in this case $\langle e_{n},e_{n}\rangle =1$. Thus $\left\langle f,e_{m}\right\rangle =\sum _{n=-\infty }^{\infty }c_{n}\left\langle e_{n},e_{m}\right\rangle =c_{m}$ and we get the formula $c_{m}=\langle f,e_{m}\rangle =\int _{0}^{1}f(t)e^{-2\pi imt}\,dt=\int _{0}^{1}f(t){\overline {g(t)}}\,dt$ Since $\displaystyle {\overline {g(t)}}=e^{-2\pi imt}$ we have $\displaystyle g(t)=e^{2\pi imt}$, and so we overall find that $\displaystyle c_{n}=\langle t^{2}-t,e^{2\pi int}\rangle$

Click here for similar questions

MER CH flag, MER QGQ flag, MER QGS flag, MER QGT flag, MER Tag Fourier series, Pages using DynamicPageList parser function, Pages using DynamicPageList parser tag