MATH101 April 2011
• Q1 (a) • Q1 (b) • Q1 (c) • Q1 (d) • Q1 (e) • Q1 (f) • Q1 (g) • Q1 (h) • Q1 (i) • Q1 (j) • Q2 (a) • Q2 (b) • Q3 (a) • Q3 (b) • Q4 (a) • Q4 (b) • Q4 (c) • Q4 (d) • Q5 (a) • Q5 (b) • Q5 (c) • Q6 (a) • Q6 (b) • Q7 • Q8 •
Question 06 (b)
Use part (a) to determine an approximation of the following definite integral
so that the error in the approximation satisfies
Remember to justify your answer.
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?
If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint.
With a convergent power series, you can integrate term by term.
For an alternating series, the error is less than or equal to the absolute value of the first neglected term.
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We saw from part (a) that we have the series expansion
and so we can write that
where the st term is
Since this is an alternating sequence which converges to zero, we have that the error when neglecting everything past the st term. Thus
if we want this to be less than , then we can choose , where the error will be less than
which works fine since it is clearly even less than .
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