Science:Math Exam Resources/Courses/MATH200/April 2012/Question 06 (b)

{{#incat:MER QGQ flag|{{#incat:MER QGH flag|{{#incat:MER QGS flag|}}}}}}

MATH200 April 2012

  •  Q1 (a)  •  Q1 (b)  •  Q2 (a)  •  Q2 (b)  •  Q3  •  Q4 (a)  •  Q4 (b)  •  Q4 (c)  •  Q5 (a)  •  Q5 (b)  •  Q6 (a)  •  Q6 (b)  •  Q7  •  Q8  •  Q9  •  Q10  •  

   Other MATH200 Exams

  •  April 2012  •  December 2011  •  

Question 06 (b)
Evaluate $I$ from part (a) if $f(x,y)={\frac {\exp(x)}{2-x}}$

Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?

If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint.

Hint 1
Using the solution of part (a), we calculate the integral $\displaystyle \int _{-1}^{2}\int _{x^{2}}^{x+2}{\frac {\exp(x)}{2-x}}\;{\text{d}}y{\text{d}}x$ It make sense to use the order of integration, where we first integrate with respect to $\displaystyle y$, since integration with respect to $\displaystyle x$ first is very hard with this integrand.

Hint 2
After integration with respect to $\displaystyle y$, you need to integrate $\displaystyle \int _{-1}^{2}{\frac {\exp(x)}{2-x}}\left(x+2-x^{2}\right){\text{d}}x$ Factorize the term in the brackets, then use integration by parts.

Checking a solution serves two purposes: helping you if, after having used all the hints, you still are stuck on the problem; or if you have solved the problem and would like to check your work. If you are stuck on a problem: Read the solution slowly and as soon as you feel you could finish the problem on your own, hide it and work on the problem. Come back later to the solution if you are stuck or if you want to check your work. If you want to check your work: Don't only focus on the answer, problems are mostly marked for the work you do, make sure you understand all the steps that were required to complete the problem and see if you made mistakes or forgot some aspects. Your goal is to check that your mental process was correct, not only the result.

Solution

Using our answer from part (a), we can write I with the given ƒ as $I=\int _{-1}^{2}\int _{x^{2}}^{x+2}{\frac {\exp(x)}{2-x}}\,dydx.$ We can evaluate the integral as follows: ${\begin{aligned}I&=\int _{-1}^{2}\int _{x^{2}}^{x+2}{\frac {\exp(x)}{2-x}}\,dydx\\&=\int _{-1}^{2}{\frac {\exp(x)}{2-x}}\left(x+2-x^{2}\right)\,dx\\&=\int _{-1}^{2}{\frac {\exp(x)}{2-x}}(-x+2)(x+1)\,dx\\&=\int _{-1}^{2}\exp(x)(x+1)\,dx.\end{aligned}}$ Using integration by parts, with u=x+1 and dv = exp(x), ${\begin{aligned}I&=\int _{-1}^{2}\exp(x)(x+1)\,dx\\&=\exp(x)(x+1){\Big \vert }_{-1}^{2}-\int _{-1}^{2}\exp(x)\,dx\\&=3\exp(2)-\left(\exp(x){\Big \vert }_{-1}^{2}\right)=2\exp(2)+\exp(-1)\end{aligned}}$ Therefore, ${\color {blue}\int _{-1}^{2}\int _{x^{2}}^{x+2}{\frac {\exp(x)}{2-x}}\,dydx=2e^{2}+e^{-1}}$

{{#incat:MER CT flag||

Click here for similar questions

MER QGH flag, MER QGQ flag, MER QGS flag, MER QGT flag, MER Tag Multiple integral, Pages using DynamicPageList3 parser function, Pages using DynamicPageList3 parser tag, Pages with math render errors

}}