Science:Math Exam Resources/Courses/MATH103/April 2016/Question 06 (a) (iv)
• Q1 (a) • Q1 (b) • Q1 (c) • Q1 (d) • Q1 (e) • Q2 (a) • Q2 (b) • Q2 (c) • Q2 (d) • Q3 • Q4 (a) • Q4 (b) • Q5 (a) • Q5 (b) • Q6 (a) (i) • Q6 (a) (ii) • Q6 (a) (iii) • Q6 (a) (iv) • Q6 (a) (v) • Q6 (b) (i) • Q6 (b) (ii) • Q6 (b) (iii) • Q7 (a) (i) • Q7 (a) (ii) • Q7 (b) (i) • Q7 (b) (ii) • Q8 (a) • Q8 (b) • Q8 (c) • Q8 (d) • Q9 (a) • Q9 (b) • Q9 (c) • Q9 (d) •
Question 06 (a) (iv) 

Solve the differential equation in part (ii) for with the initial condition found in part (ii). For full credit you must show your work. 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint. 
Hint 1 

Note that the differential equation in part (ii) is separable. 
Hint 2 

Consider using partial fractions. 
Checking a solution serves two purposes: helping you if, after having used all the hints, you still are stuck on the problem; or if you have solved the problem and would like to check your work.

Solution 

Found a typo? Is this solution unclear? Let us know here.
Please rate my easiness! It's quick and helps everyone guide their studies. We can rewrite the differential equation in the following separable form: Integrating both sides, we get We first compute the right hand side: The left hand side can be computed using partial fractions: (Note: Since the population will never be negative nor exceed the carrying capacity, , so the absolute value signs in the antiderivatives can be omitted.) Returning to we have Thus
We finally have which yields 