|Thread title||Replies||Last modified|
|Unclear solution||3||02:39, 19 March 2018|
For MATH152/April 2016/Question A 29, the solution would be very unclear for students as no explanation is given for how to obtain the eigenvector. Perhaps explain how such an eigenvector can be obtained by computing the characteristic polynomial, finding zeroes, and then calculating non-zero solutions in the corresponding linear systems.
Thanks for pointing out. You are completely right, that was written in the beginning, I didn't really realize how important to student details are. I will correct it and change flags.
Would you mind spending a few minutes checking it, It seems different from previous solution.