Science talk:Math Exam Resources/Courses/MATH100/December 2010/Question 1 (n)

I think we need another category for this - somehow we need to identify problems that are antidifferentiating for the tail end of diff calc courses.

When you differentiate

$\left({\sqrt {t}}^{3}\right)'=\left(t^{3/2}\right)'={\frac {3t^{1/2}}{2}},$

hence

$f'(t)=\left(2{\sqrt {t}}^{3}-5t+6\right)'=2{\frac {3{\sqrt {t}}}{2}}-5=3{\sqrt {t}}-5\not =6{\sqrt {t}}-5.$

So the step from $f'(t)$ to ƒ(t) needs to be fixed.