Science:Math Exam Resources/Courses/MATH437/December 2011/Question 07 (ii)
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Question 07 (ii) 

Let such that and let . (ii) For each odd integer x, prove that there exists a unique and a unique such that 
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If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! 
Hint 

Part (i) shows us that the order of a modulo is equal to . Thus each of are distinct odd numbers and thus each of the are also distinct odd numbers. Hence it suffices to show that for any and finish off the proof with a counting argument. 
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Solution 

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Please rate my easiness! It's quick and helps everyone guide their studies. Repeating the hint, part (i) shows us that the order of a modulo is equal to . Thus each of are distinct odd numbers between 0 and for and thus each of the are also distinct odd numbers between 0 and . As there are total odd numbers between 0 and , we know that provided all of the above numbers are distinct, we have found total odd numbers and hence we can form a bijection. Hence it suffices to show that for any . This shows the claim for all odd numbers since all odd numbers are equivalent modulo to an odd number between 0 and . Assume towards a contradiction that we found two such numbers: Without loss of generality, suppose that . Then, Once again, modulo 4 arguments (recalling that ) show that the left hand side above is congruent to 1 modulo 4 and the right hand side is still congruent to 1 modulo 4. This is a contradiction. Thus any odd number can be expressed uniquely of the form with and as required. 