Science:Math Exam Resources/Courses/MATH215/December 2011/Question 03 (a)

MATH215 December 2011

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Question 03 (a)
For the following ODE ${\frac {dy}{dt}}=(y^{2}-1)(y-2)^{2}$ (a) Determine the equilibrium (fixed) points.

Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you?

If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it!

Hint
The value of a solution in equilibrium does not change. What does this mean for the derivative?

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Solution
Found a typo? Is this solution unclear? Let us know here. Please rate my easiness! It's quick and helps everyone guide their studies. Setting ${\frac {dy}{dt}}=(y^{2}-1)(y-2)^{2}=0$ we have $y=\pm 1,2$ as our equilibrium points.

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