Science:Math Exam Resources/Courses/MATH105/April 2012/Question 08 (a)
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Question 08 (a) 

Shortanswer questions. No credit will be given for the answer (even if it is correct) without the accompanying work. The Maclaurin series for arctan x is given by which has radius of convergence equal to 1. Use this fact to compute the exact value of the series below: (Hint: Note that ). 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint. 
Hint 1 

By a visual inspection, we see that the terms that don't match up to the expression for are the terms corresponding to and to (moving the denominator up to the numerator). Thus, we want to get these two terms to match. How can we rearrange these terms to achieve this goal? 
Hint 2 

Utilize the hint given and note

Checking a solution serves two purposes: helping you if, after having used all the hints, you still are stuck on the problem; or if you have solved the problem and would like to check your work.

Solution 

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Please rate my easiness! It's quick and helps everyone guide their studies. To evaluate , we need to make it look more like for some x. Both sums start with , have , and have a in the denominator. Therefore, we need that . Following the hint, we write which we can make even more similar to by writing it as . Let's write out the two sums again and see how close we are: and we wish to evaluate . If , the only difference between the two sums now is a factor of , which doesn't depend on n. We can multiply S by (and put that factor in the sum) and also divide S by that same factor (keeping it outside the sum): 