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03:5303:53, 19 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07 ‎No edit summary current
03:5203:52, 19 March 2020 diff hist +424‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07/Solution 1 ‎No edit summary current
03:3303:33, 19 March 2020 diff hist +389‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07/Solution 1 ‎No edit summary
03:2403:24, 19 March 2020 diff hist +78‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07/Solution 1 ‎ Created page with "By definition <math>f'(2) = \lim_{x\to 2}\frac{f(x) - f(2)}{x - 2} = 3</math>"
03:2303:23, 19 March 2020 diff hist +26‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07/Hint 1 ‎ Created page with "The derivative is a limit." current
03:2203:22, 19 March 2020 diff hist +116‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07/Statement ‎ Created page with "Use the '''definition of the derivative''' to calculate <math>f'(2)</math> for <math>f(x) = \frac{1}{1 - 2x}</math>." current
03:2003:20, 19 March 2020 diff hist +718‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 07 ‎ Created page with "  <!-- second letter is for..."
03:1903:19, 19 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06 ‎No edit summary current
03:1803:18, 19 March 2020 diff hist +14‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06/Hint 1 ‎No edit summary current
03:1803:18, 19 March 2020 diff hist +17‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06/Hint 1 ‎No edit summary
03:1703:17, 19 March 2020 diff hist +39‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06/Solution 1 ‎ Created page with "<math>\lim_{x\to a} f(x) = f(a)</math>." current
03:1703:17, 19 March 2020 diff hist +54‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06/Hint 1 ‎ Created page with "Just refer to the definition. No tricky business here."
03:1603:16, 19 March 2020 diff hist +114‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06/Statement ‎ Created page with "Write the definition of a function <math>f(x)</math> being continuous at a point <math>x = a</math> in its domain." current
03:1503:15, 19 March 2020 diff hist +718‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 06 ‎ Created page with "  <!-- second letter is for..."

04:4104:41, 18 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎No edit summary current
04:3704:37, 18 March 2020 diff hist +337‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a)/Solution 1 ‎ Created page with "The slope of the tangent line to the curve <math>y = f(x)</math> is equal to <math>f'(x)</math>. <math>f'(10) = \frac{1}{(1+10)^2} = \frac{1}{121}</math>. Using the slope-poi..."
04:2904:29, 18 March 2020 diff hist +124‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a)/Hint 1 ‎ Created page with "For a curve described by a function, at any point, the slope of the tangent line is equal to the derivative of the function." current
04:2004:20, 18 March 2020 diff hist +357‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a)/Statement ‎ Created page with "For this question, let <math>f(x) = 1 - (1+x)^{-1}</math> You may use the following facts without proving them: * <math>f(x) = \frac{x}{1+x}</math> * <math>f(x) = \frac{1}{(..." current
04:1804:18, 18 March 2020 diff hist −7,559‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ Replaced content with "  <!-- second letter is..." Tag: Replaced
04:1804:18, 18 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (d) ‎No edit summary current
04:1504:15, 18 March 2020 diff hist +196‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (d)/Solution 1 ‎ Created page with "By definition, the average rate of change from <math>x = 0</math> to <math>x = 10</math> is <math>\frac{f(10) - f(0)}{10 - 0} = \frac{1}{10}\left( \frac{10}{11} - 0 \right) =..." current
04:1104:11, 18 March 2020 diff hist +97‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (d)/Hint 1 ‎ Created page with "Use the definition of the average rate of change of a function. Remember to simplify your answer." current
04:1004:10, 18 March 2020 diff hist +358‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (d)/Statement ‎ Created page with "For this question, let <math>f(x) = 1 - (1+x)^{-1}</math> You may use the following facts without proving them: * <math>f(x) = \frac{x}{1+x}</math> * <math>f(x) = \frac{1}{(..." current
04:0904:09, 18 March 2020 diff hist +718‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (d) ‎ Created page with "  <!-- second letter is for..."
04:0804:08, 18 March 2020 diff hist +7‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (b)/Solution 1 ‎No edit summary current
04:0504:05, 18 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (c) ‎No edit summary current
04:0404:04, 18 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (c)/Solution 1 ‎No edit summary current
04:0304:03, 18 March 2020 diff hist +222‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (c)/Solution 1 ‎ Created page with "Recall that the template for a Hill function is <math>\frac{Ax^n}{a^n + x^n}<\math>. The half-maximal activation level is obtained when <math>x = a</math>. In our case here,..."
03:5803:58, 18 March 2020 diff hist +142‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (c)/Hint 1 ‎ Created page with "Use the definition of half-max of a Hill function. Note that the current problem asks for the value of <math>x</math> that gives the half-max." current
03:5603:56, 18 March 2020 diff hist +350‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (c)/Statement ‎ Created page with "For this question, let <math>f(x) = 1 - (1 + x)^{-1}</math> You may use the following facts without proving them: * <math>f(x) = \frac{x}{1+x}</math> * <math>f(x) = \frac{1}..." current
03:5403:54, 18 March 2020 diff hist +718‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (c) ‎ Created page with "  <!-- second letter is for..."
00:1700:17, 18 March 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (b) ‎No edit summary current
00:1600:16, 18 March 2020 diff hist +161‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (b)/Solution 1 ‎ Created page with "<math>f''(10) = \frac{-2}{(1+10)^3} = \frac{-2}{11^3} < 0.</math> Therefore, the tangent line as a linear approximation is an overestimate of <math>f(x)</math>."
00:1300:13, 18 March 2020 diff hist +128‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (b)/Hint 1 ‎ Created page with "Think about the concavity of <math>f(x)</math>. For example, if it is concave up, its graph will lie on top of its tangent line." current
00:1000:10, 18 March 2020 diff hist +391‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (b)/Statement ‎ Created page with "For this question, let <math>f(x) = 1 - (1+x)^{-1}</math> You may use the following facts without proving them: * <math>f(x) = \frac{x}{1+x}</math> * <math>f(x) = \frac{1}{(..." current
00:0000:00, 18 March 2020 diff hist +718‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (b) ‎ Created page with "  <!-- second letter is for..."

23:5023:50, 17 March 2020 diff hist +14‎ N User:MingfengQiu ‎ Created page with "Test test test" current Tag: Visual edit: Switched
23:4223:42, 17 March 2020 diff hist +360‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎No edit summary Tag: Visual edit
23:3623:36, 17 March 2020 diff hist −81‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ →‎Solution Tag: Visual edit
23:3323:33, 17 March 2020 diff hist −59‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ →‎Question 05 (a) Tag: Visual edit
23:3123:31, 17 March 2020 diff hist +151‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ →‎Hint Tag: Visual edit
23:2823:28, 17 March 2020 diff hist +80‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ →‎Question 05 (a)
23:2623:26, 17 March 2020 diff hist +347‎ Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ →‎Question 05 (a) Tag: Visual edit
23:0923:09, 17 March 2020 diff hist +7,479‎ N Science:Math Exam Resources/Courses/MATH102/December 2019/Question 05 (a) ‎ Created page with "<span></span><div style="font-size:18pt; line-height:100%; color:#ffffff; background:#2F4F4F; position: relative; padding:1ex;">'''MATH102''' '''December 2019'''</div> File:..." Tag: Visual edit

23:4923:49, 15 February 2020 diff hist 0‎ Science:Math Exam Resources/Courses/MATH100/December 2018/Question 04 ‎No edit summary
23:4523:45, 15 February 2020 diff hist +1,491‎ N Science:Math Exam Resources/Courses/MATH100/December 2018/Question 04/Solution 1 ‎ Created page with "Let <math> (x_0, y_0) </math> be a point on the curve. Then <math> x_0^2 + 2y_0^2 = 8.~~~~(1) </math> To find the slope of the tangent line passing through <math> (x_0, y_0)..."
23:0823:08, 15 February 2020 diff hist +2‎ Science:Math Exam Resources/Courses/MATH100/December 2018/Question 04/Hint 2 ‎No edit summary current
23:0823:08, 15 February 2020 diff hist +162‎ N Science:Math Exam Resources/Courses/MATH100/December 2018/Question 04/Hint 2 ‎ Created page with "Write the equation of the tangent line at an arbitrary point <math>(x_0, y_0)</math>on this curve, using the point-slope formula. Let this line go through (0,-6)."
23:0323:03, 15 February 2020 diff hist +90‎ N Science:Math Exam Resources/Courses/MATH100/December 2018/Question 04/Hint 1 ‎ Created page with "To find the slope of the tangent line at a point of a curve, use implicit differentiation." current
22:5922:59, 15 February 2020 diff hist +223‎ N Science:Math Exam Resources/Courses/MATH100/December 2018/Question 04/Statement ‎ Created page with "Find the <math>x</math> and <math>y</math> coordinates of all points on the curve given by the equation: <math> x^2 + 2y^2 = 8 </math> for which the tangent line at each of..." current Tag: Visual edit: Switched

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