Science talk:Math Exam Resources/Courses/MATH152/April 2016/Question A 17

Hey, Thanks for your very detailed solution to this question. Just a few comments: 1. The example you give for (a) is trivial. If all the entries of M are zeros, the linear system does not even exist. I think it would be better if we start with the augmented matrix [M |b]. After we achieve the reduced row echelon form, if there is one zero row in M, but the corresponding entry in b is non-zero, then no solution.

2. I think for a linear system, the possible number of solutions are 0, unique or infinitely many. In this case, I do not think that (c) is correct.

If you agree with my comments, can you please review the solution?

Thanks. Aili

I agree with you. The current solution should be revised.