# Science talk:Math Exam Resources/Courses/MATH103/April 2009/Question 4 (b)

- [View source↑]
- [History↑]

## Contents

Thread title | Replies | Last modified |
---|---|---|

How to get du | 1 | 04:25, 10 April 2012 |

Jump to content
# Science talk:Math Exam Resources/Courses/MATH103/April 2009/Question 4 (b)

## Contents

From UBC Wiki

- [View source↑]
- [History↑]

Thread title | Replies | Last modified |
---|---|---|

How to get du | 1 | 04:25, 10 April 2012 |

How do you get du? In the solution it looks like du = 2ln(x)*(1/x)dx Do you just use the chain rule where f(x)=x^2 and g(x)=lnx?

03:27, 10 April 2012

Yes, this is exactly what you do! The solution now show an extra step.

Bernhard Konrad04:25, 10 April 2012