Science talk:Math Exam Resources/Courses/MATH103/April 2009/Question 4 (b)
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| Thread title | Replies | Last modified |
|---|---|---|
| How to get du | 1 | 04:25, 10 April 2012 |
| Thread title | Replies | Last modified |
|---|---|---|
| How to get du | 1 | 04:25, 10 April 2012 |
How do you get du? In the solution it looks like du = 2ln(x)*(1/x)dx Do you just use the chain rule where f(x)=x^2 and g(x)=lnx?
Yes, this is exactly what you do! The solution now show an extra step.