Science:Math Exam Resources/Courses/MATH307/December 2012/Question 06 (e)/Solution 1

From part (c), $A^{-1}=V\Sigma ^{-1}U^{T}$, and using the same logic as part (c) we find that $\left\|A^{-1}\right\|=\|\Sigma ^{-1}\|=2$. The condition number is then

$\left\|A^{-1}\right\|\cdot \left\|A\right\|=2\cdot 2=4.$