Science:Math Exam Resources/Courses/MATH307/December 2010/Question 01 (d)/Solution 1

From UBC Wiki

For convenience, let's recall our results from part (b) and part(c):

and cond(A) is not defined when a = 0. This suggests considering three cases for :

  • Case 1: If then
  • Case 2: If then
  • Case 3: If then

So, the sketch looks like this:

A vs condA.jpg