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Science:Math Exam Resources/Courses/MATH152/April 2016/Question A 23/Solution 2

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Alternatively, we can also use row reduction.

Form the augmented matrix [A|I]= [213100101010012001]

Interchange R2 and R1 : [101010213100012001]

R22R1R2 : [101010011120012001]

R3R2R3 : [101010011120001121]

R1R3R1 : [100111011120001121]

R2R3R2 : [100111010241001121]

Therefore,

A1=[111241121].