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Science
:
Math Exam Resources/Courses/MATH152/April 2015/Question A 01/Solution 1
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From UBC Wiki
<
Science:Math Exam Resources
|
Courses/MATH152
|
April 2015
|
Question A 01
By definition, we have
2
u
=
2
(
1
−
i
)
=
2
−
2
i
,
{\displaystyle 2u=2(1-i)=2-2i,}
and hence
z
+
2
u
=
(
1
+
3
i
)
+
(
2
−
2
i
)
=
(
1
+
2
)
+
(
3
−
2
)
i
=
3
+
i
.
{\displaystyle z+2u=(1+3i)+(2-2i)=(1+2)+(3-2)i=\color {blue}3+i.}