Jump to content

Science:Math Exam Resources/Courses/MATH110/December 2013/Question 06 (b)/Solution 1

From UBC Wiki

Since we have simplified, we can simply apply the chain rule to it using u=x3+2x2+x−3.

f(u)=euf′(u)=euu(x)x3+2x2+x−3u′(x)=3x2+4x+1.

Combining, we get:

f′(x)=(3x2+4x+1)⋅ex3+2x2+x−3