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Science:Math Exam Resources/Courses/MATH110/April 2016/Question 08 (a)/Solution 1

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We want to approximate the value

14.16.

To this end, we define the function f(x)=1x.

We will use a linear approximation:

f(x)≈f(a)+f′(a)(x−a)

We want to use x=4.16 and a=4. It is necessary to compute f′(4). The derivative of f(x) is

f′(x)=−1x2

so

f′(4)=−142=−116

so

f(4.16)≈14−116(4.16−4)

and therefore

f(4.16)≈0.25−0.1616

and we get the approximation

f(4.16)≈0.24.

This is believable because we expect to get something just a little less than 0.25, since we are dividing by a number that is just a little more than 4.

Answer: 14.16≈0.24