By the Divergence Test, we must have that the terms of n a n − 2 n + 1 n + 1 {\displaystyle {\frac {na_{n}-2n+1}{n+1}}} approach zero as n → ∞ {\displaystyle n\rightarrow \infty } . Thus, lim n → ∞ n a n − 2 n + 1 n + 1 = 0 {\displaystyle \lim _{n\rightarrow \infty }{\frac {na_{n}-2n+1}{n+1}}=0} . Can you use this to obtain more information about the terms of a n {\displaystyle a_{n}} ?
