Science:Math Exam Resources/Courses/MATH105/April 2014/Question 01 (b)/Solution 1

Setting $V=\pi$,

${\begin{aligned}{\frac {\pi x^{2}y}{3}}&=\pi \\x^{2}y&=3\\y&={\frac {3}{x^{2}}}\\\end{aligned}}$

We plot the equation $y={\frac {3}{x^{2}}}$ noting that $x\geq 0$ is necessary for the curve to make physical sense.