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Science
:
Math Exam Resources/Courses/MATH103/April 2012/Question 01 (f)/Solution 1
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From UBC Wiki
<
Science:Math Exam Resources
|
Courses/MATH103
|
April 2012
|
Question 01 (f)
Recall that
ln
(
1
−
x
)
=
−
x
−
x
2
2
−
x
3
3
−
⋯
,
{\displaystyle \displaystyle \ln(1-x)=-x-{\frac {x^{2}}{2}}-{\frac {x^{3}}{3}}-\cdots ,}
therefore
x
ln
(
1
−
x
)
=
−
x
2
−
x
3
2
−
x
4
3
−
⋯
{\displaystyle \displaystyle x\ln(1-x)=-x^{2}-{\frac {x^{3}}{2}}-{\frac {x^{4}}{3}}-\cdots }
The coefficient of
x
3
term is -1/2 and so the correct answer is D.