The Euler’s method has form y n + 1 = y n + Δ t f ( y n ) , {\displaystyle y_{n+1}=y_{n}+\Delta tf(y_{n}),} where f ( y ) {\displaystyle f(y)} is the derivative of y {\displaystyle y} , i. e. d y d t = f ( y ) {\displaystyle {\frac {dy}{dt}}=f(y)} .
