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Science:Math Exam Resources/Courses/MATH101 A/April 2024/Question 12/Solution 1

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Since the series n=1cos(θn) converges, it must be that the terms of the sum converge to 0: limncos(θn)=0. This is a consequence of Theorem 3.3.1 in CLP . Note in particular that it does not matter what precise value the series converges to.

We see then that, for large n, the number cos(θn) is approximately 0. Since cos is a continuous function, it follows that θnπ2+kπ, where k is some integer. But the only integer k for which π2+kπ is in the range (0,3) is 0.

Therefore the sequence θn converges to π2.