Since the two curves y 1 = f ( x ) = 4 − ( x − 1 ) 2 {\displaystyle y_{1}=f(x)=4-(x-1)^{2}} and y 2 = g ( x ) = x + 1 {\displaystyle y_{2}=g(x)=x+1} intersects when
Thus, the curves intersect at x=-1 and x=2. Moreover, from the sketch, we can see that f(x) > g(x) in the interval [-1, 2].
Therefore, the area A bounded by the curves is given by: