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Science:Math Exam Resources/Courses/MATH101/April 2011/Question 04 (a)/Hint 1

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< Science:Math Exam Resources‎ | Courses/MATH101‎ | April 2011‎ | Question 04 (a)(Redirected from Science:Math Exam Resources/Courses/MATH101/April 2011/Question 4 (a)/Hint 1)

If $u={\sqrt {x}}$ , then $du={\frac {1}{2{\sqrt {x}}}}dx$ .

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