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Science:Math Exam Resources/Courses/MATH100/December 2018/Question 05 (a)/Solution 1

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We take the derivative f′(x)=97(x27+x−57)=97⋅x+1x57. The function therefore has two critical points: at x=−1,0. Now using a chart of signs shows that f′(x) exactly when x∈(−1,0). We conclude that f(x) is decreasing on (−1,0) and increasing on (−∞,−1)∪(0,+∞).