Jump to content
Toggle sidebar
UBC Wiki
Search
Log in
hide
Navigation
Create a New Page
Main Page
Categories
Contents
Recent changes
Help & Support
Wiki Spaces
Main
Course
Documentation
Sandbox
UBC Wiki Books
Tools
What links here
Related changes
Upload file
Special pages
Printable version
Permanent link
Page information
Embed Page
Science
:
Math Exam Resources/Courses/MATH100/December 2016/Question 02 (b)/Solution 1
Science
Discussion
English
Read
View source
View history
More
Read
View source
View history
From UBC Wiki
<
Science:Math Exam Resources
|
Courses/MATH100
|
December 2016
|
Question 02 (b)
By the quotient rule,
g
′
(
x
)
=
(
2
x
)
(
2
x
−
1
)
−
(
x
2
+
3
)
(
2
)
(
2
x
−
1
)
2
=
4
x
2
−
2
x
−
2
x
2
−
6
(
2
x
−
1
)
2
=
2
(
x
2
−
x
−
3
)
(
2
x
−
1
)
2
.
{\displaystyle {\begin{aligned}g'(x)&={\frac {(2x)(2x-1)-(x^{2}+3)(2)}{(2x-1)^{2}}}\\&={\frac {4x^{2}-2x-2x^{2}-6}{(2x-1)^{2}}}\\&={\color {blue}{\frac {2(x^{2}-x-3)}{(2x-1)^{2}}}}.\\\end{aligned}}}