Course:MATH110/Archive/2010-2011/003/Groups/Group 06/Homework 4

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Problem 1

Five persons named their pets after each other. From the following clues, can you decide which pet belongs to Suzan's mother?

Tosh owns a cat, Bianca owns a frog that she loves, Jaela owns a parrot which keeps calling her "darling, darling", Jun owns a snake, don't mess with him, Suzan is the name of the frog, The cat is named Jun, The name by which they call the turtle is the name of the woman whose pet is Tosh, Finally, Suzan's mother's pet is Bianca.

At first this might seem puzzling because it looks as though there are six people because Suzan's mother might be another person. How they've worded the question seems to hint that one of the 5 people who isn't Suzan is her mother.

The second way you could approach the problem would be to eliminate all of the choices with logic and narrow down the corresponding names to what type of pet Suzan's mother owns. Susan's mother could be any of these people because you don't want to assume Tosh or Jun are men.


So you could start by making a chart about which animal belongs to who.

Tosh - cat

Bianca - frog

Jaela - parrot

Jun - snake

Suzan - turtle

You can get this list easily by reading the question and eliminating all the choices of animals but the turtle, which must belong to Suzan. Now you have to figure out the names of the pets which will help you figure out who Bianca belongs to and what kind of animal she is.

Tosh - cat - named Jun

Bianca - frog - named Suzan

Jaela - parrot named ?

Jun - snake - named?

Suzan - turtle - named ?

The name by which they call the turtle is the same as the name of the woman whose pet is Tosh. Suzan's pet is a turtle who can't be named Bianca, Suzan, Jun or Tosh. Jaela is the only name left, so the turtle is named Jaela. Tosh's owner = name of turtle. That must mean that Jaela's pet parrot is named Tosh. So we have

Tosh - cat - named Jun

Bianca - frog - named Suzan

Jaela - parrot named Tosh

Jun - snake - named ?

Suzan - turtle - named Jalea

The only name missing is Bianca, Suzan's mother's pet. So Suzan's mother must be Jun who owns a pet snake named Bianca.


Problem 2

Bohao, Stewart, Dylan, Tim and Chan are the five players of a basketball team. Two are left handed and three right handed, Two are over 2m tall and three are under 2m, Bohao and Dylan are of the same handedness, whereas Tim and Chan use different hands. Stewart and Chan are of the same height range, while Dylan and Tim are in different height ranges. If you know that the one playing centre is over 2m tall and is left handed, can you guess his name?

--> 3 people are right handed and 2 are left, it goes to say Bahao and Dylan are right handed (if Tim and Chan use different hands one of them must be right handed); this also leaves Stewart to be left handed (only 2 people are left handed and if one of them is Tim or Chan the other must be Stewart). With 3 people being under 2m tall, Stewart and Chan being the same height must be under 2m (if Dylan and Tim are different height, one must be under 2); leaving Bahao to be over 2m (if only 2 are over and Dylan and Tim are different only one of them can be over 2m leaving Bahao). You know the centre has to be left handed and over 2m. The only person left on the chart is Tim, who has nothing to his name as of yet. Only 2 people can be over 2m and if the centre is left handed it cannot be Bahao. By elimination Dylan is excluded because he is right handed, Chan and Stewart are under 2m. Tim is the only person left you can fit the qualifications. Tim must be Left handed and over 2m.

  • Bahao - Right Hand - Over 2m
  • Dylan - Right Hand -
  • Tim -
  • Chan - - Under 2m
  • Stewart - Left Hand - Under 2m

Since you know the center, who is left handed and over 2m, is Tim, you can fill out the rest of the chart.

  • Bahao - Right Hand - Over 2m
  • Dylan - Right Hand - Under 2m
  • Tim - Left Hand - Over 2m - Centre
  • Chan - Right Hand - Under 2m
  • Stewart - Left Hand - Under 2m


Problem 3

Adam, Bobo, Charles, Ed, Hassan, Jason, Mathieu, Pascal and Sung have formed a baseball team. The following facts are true:

   * Adam does not like the catcher,
   * Ed's sister is engaged to the second baseman,
   * The centre fielder is taller than the right fielder,
   * Hassan and the third baseman live in the same building,
   * Pascal and Charles each won $20 from the pitcher at a poker game,
   * Ed and the outfielders play cards during their free time,
   * The pitcher's wife is the third baseman's sister,
   * All the battery and infield except Charles, Hassan and Adam are shorter than Sung,
   * Pascal, Adam and the shortstop lost $100 each at the race track,
   * The second baseman beat Pascal, Hassan, Bobo and the catcher at billiards,
   * Sung is in the process of getting a divorce,
   * The catcher and the third baseman each have two legitimate children,
   * Ed, Pascal Jason, the right fielder and the centre fielder are bachelors, the others are all married
   * The shortstop, the third baseman and Bobo all attended the fight,
   * Mathieu is the shortest player of the team, 

Determine the positions of each player on the baseball team.

Note: On a baseball team there are three outfielders (right, centre and left), four infielders (first baseman, second baseman, third baseman and shortstop) and the battery (pitcher and catcher).

This question is best answered by using a graph I believe, First I started by putting the players names on the top of a chart and the positions on the side and going through the list and crossing off any of the players that don't fit the qualifications.

Go through the list and cancel qualifications for example Adam does not like the catcher---he's not the catcher Ed's sister is engaged to the second baseman---- Ed is not the Second baseman and the second baseman is not a batchelor going on Pascal and Charles cannot be the pitcher Ed cannot be the outfielder Charles Hassan and Adam are shorter than sung Pascal and Adam are not the short stop Ed, Pascal Jason the right fielder and the center fielder means they are batchelors making the others married I used M to indicate married and B for Batchelor in my graph Using Height Marriage and qualifications I was able to deduct and finish this graph and the following players for each position are:

Adam: third baseman Charles: catcher Ed: shortstop Hassan: pitcher Jason: second baseman Pacal: first baseman Sung: left field Mathieu: right field Bobo: center field

http://co102w.col102.mail.live.com/att/GetAttachment.aspx?tnail=0&messageId=96be92f2-dc13-11df-8bdc-00237de49116&Aux=4%7C0%7C8CD3E377DC9AB80%7C%7C0%7C0%7C0%7C0%7C%7C&maxwidth=220&maxheight=160&size=AttFile:IMG0022-20101019-2329.jpg

so the graph came out really small so it will be submitted as written work on wednesday

Problem 4 Solution 1

Six players - Petra, Carla, Janet, Sandra, Li and Fernanda - are competing in a chess tournament over a period of five days. Each player plays each of the others once. Three matches are played simultaneously during each of the five days. The first day, Carla beats Petra after 36 moves. The second day, Carla was again victorious when Janet failed to complete 40 moves within the required time limit. The third day had the most exciting match of all when Janet declared that she would checkmate Li in 8 moves and succeeded in doing so. On the fourth day, Petra defeated Sandra. Who played against Fernanda on the fifth day?

There are 5 days in the tournament. Each day there will be three matches being played simultaneously, with a total of three matches per day. 'No girl will be playing more than 1 girl per day, if girl A is playing girl B then girl B is playing girl A'

This problem can be solved using a grid sized 6 by 6. Along the horizontal axis, mark the days of the tournament. Along the vertical axis, mark the girls (identified by a number).

Diagram 1.jpg

Fill the interior of the box like this: Line up the day and the name of the girl, and in that box fill in the number of the girl that she is playing.

Start with what we know:

Day 1: Carla beats Petra

Day 2: Carla beats Janet

Day 3: Janet beats Li

Day 4: Petra beats Sandra

Day 5: Fernanda plays who? - The goal of the question.

Fill in the columns. For example, to note that Carla beat Petra on Day 1, line up Carla (row 1) and day 1 (column 2), and input into that box the number 3 (which represents Petra).

Math 2.JPG

Next, fill in the box further using the principle that each girl can only play one other girl, that each girl plays only one game per day, that if girl a is playing girl b then girl b is playing girl a.

For example, Carla is playing Petra on day one, therefore Petra is playing Carla on day 1. Fill in the appropriate box.

Math 3.JPG

Next, fill in all of the boxes such that each of the 6 rows and 6 column contains each of the numbers 1-6 and therefore not more than 1 of each of the digits 1-6. This requires filling in numbers at first arbitrarily, then using logical deduction and re-editing the numbers until you have a working cube.

Math 5.JPG

Therefore, Fernanda will play Carla on the last day.

Problem 4 Solution 2

From looking at the match ups you can immediately conclude that Janet must play Petra on the fifth day because both are busy not playing the other on the first 4 days.


This leaves 6 possible matchups for the Friday’s game. Carla v Li, Carla, v Sandra, Carla v Fernanda Li v Sandra, Li v Fernanda Fernanda v Sandra


From here we can see that only has to play Sandra and Fernanda and since Sandra is busy on day 4, that means Janet plays Sandra on day 1 leaving the only match for Fernanda and Li eliminating Li.


Now we know that Fernanda plays Carla or Sandra

Looking at the new results we know Li plays day 1 against Fernanda, day 2 against (Petra or Sandra), day 3 against Janet, day 4 against Carla, and day 5 against (Sandra or Petra). Petra is busy day 5 against Janet so by default Li plays Petra day 2.


This leaves the only remaining match on day 2 for Fernanda and Sandra.''


Answer: Thus Fernanda plays Carla on day 5

Problem 5

Question: Homer finally had a week off from his job at the nuclear power plant and intended to spend all nine days of his vacation (Saturday through the following Sunday) sleeping late. But his plans were foiled by some of the people who work in his neighbourhood.

On Saturday, his first morning off, Homer was wakened by the doorbell; it was a salesman of magazine subscriptions.

On Sunday, the barking of the neighbour's dog abruptly ended Homer's sleep.

On Monday, he was again wakened by the persistent salesman but was able to fall asleep again, only to be disturbed by the construction workers next door.

In fact, the salesman, the neighbour's dog and the construction workers combined to wake Homer at least once each day of his vacation, with only one exception.

The salesman woke him again on Wednesday; the construction workers on the second Saturday; the dog on Wednesday and on the final Sunday.

No one of the three noisemakers was quiet for three consecutive days; but yet, no pair of them made noise on more than one day during Homer's vacation. On which day of his holiday was Homer actually able to sleep late?

Answer:

Step 1: First make a list of every day Homer is on vacation.

Saturday:

Sunday:

Monday:

Tuesday:

Wednesday:

Thursday:

Friday:

Saturday (2):

Sunday (2):

Step 2: Fill in all the information given.

Saturday: Salesman

Sunday: Dog

Monday: Salesman+Construction

Tuesday:

Wednesday: Salesman+Dog

Thursday:

Friday:

Saturday (2): Construction

Sunday (2): Dog

Step 3: Once the information given is filled in one can see that there are only three possible days that Homer could have slept in during his vacation. We are told that the none of the noise makers stayed quiet for three days straight. Thus based on the salesman noise on wednesday they would have to make noise friday or saturday, because we are also given the information that no noisemaker pairs made noise more then once. If the salesman made noise on the second saturday he would be paired with the construction workers for the second time. From this we can determine the salesman woke Homer up on Friday. Similarly the construction worker woke Homer up on monday which means he woke him up again on either Tuesday or Thursday (sticking with the information no noisemaker didn't make noise for three days straight). Based on this information the construction worker would then have to wake him up on Thursday, if he woke him up on Tuesday there would be a three day discrepancy.

Step 4: Fill in the remaining information found through your thought process above. When done it is easy to see the only day Homer can sleep in is tuesday.

Saturday: Salesman

Sunday: Dog

Monday: Salesman+Construction

Tuesday:

Wednesday: Salesman+Dog

Thursday: Construction

Friday: Salesman

Saturday (2): Construction

Sunday (2): Dog

Step 5: Homer will be able to actually sleep in on the tuesday of his vacation.