Science:Math Exam Resources/Courses/MATH101/April 2005/Question 03 (c)/Solution 1
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We want to integrate:
The first step is to complete the square in the denominator:
Now we substitute:
So the integral simplifies to
We now perform a trigonometric substitution (this step is only valid for |y| smaller than 1, which we know is true because 1-y^2 must be positive):
So the above integral becomes:
But for any u, we have
So the above quantity is equal to
So we have
This is not required in a test, but we can check our answer by differentiating: