Define f ( x ) = x 3 ∫ 0 x 3 + 1 e t 3 d t . {\displaystyle f(x)=x^{3}\int _{0}^{x^{3}+1}e^{t^{3}}dt.}
(b) Find the equation of the tangent line to the graph of y = f ( x ) {\displaystyle y=f(x)} at x = − 1 {\displaystyle x=-1} . Simplify your answer completely.
