Find f ( t ) {\displaystyle \displaystyle f(t)} , if f ″ ( t ) = 3 t {\displaystyle \displaystyle f''(t)={\frac {3}{\sqrt {t}}}} , f ( 4 ) = 2 {\displaystyle \displaystyle f(4)=2} and f ′ ( 4 ) = 7 {\displaystyle \displaystyle f'(4)=7}
