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Question 03 (b) 

ShortAnswer Questions. Question 13 are shortanswer questions. Put your answer in the box provided. Simplify your answer as much as possible. Full Marks will be awarded for a correct answer placed in the box. Show your work, for part marks. A force of 10 N (newtons) is required to hold a spring stretched 5 cm beyond its natural length. How much work, in joules (J), is done in stretching the spring from its natural length to 50 cm beyond its natural length? 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint. 
Hint 1 

Remember that force is for a spring. But what is here? 
Hint 2 

Work is force multiplied by distance, for constant force. In this case, force is not constant  what would the formula for work be? 
Checking a solution serves two purposes: helping you if, after having used all the hints, you still are stuck on the problem; or if you have solved the problem and would like to check your work.

Solution 

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Please rate my easiness! It's quick and helps everyone guide their studies. Recall for springs, We are given that force is 10 N when is 5 cm = 0.05 m, so giving . Then, the work done in stretching the spring from its natural length to 50 cm = 0.5 m beyond its natural length is given by So the work done in stretching the spring is 25J. 