UBC Wiki - User contributions [en]

GRSJ300StudentBlogs

2017-08-24T21:27:46Z

AliHussein:

Post your UBC Blog URLS here! Please follow the following format: [Firstname] [Lastname] http://blogs.ubc.ca/blogurl 
Note: use '''http://''', do not use https://

=== 2017SA-GRSJ300-98A (Instructor: Dr. Ray Hsu)===

GROUP 1
* Kate (Kathryn) McLaughlin https://blogs.ubc.ca/kathrynmcl/
* Qi Mao http://blogs.ubc.ca/qimao
* Ashley Hayes http://blogs.ubc.ca/ashleyhayes
* Sarah Siska http://blogs.ubc.ca/sarahsiska/
* Angelina Sung http://blogs.ubc.ca/angelinasung/2017/06/27/angelinasung/
* Lara Jung http://blogs.ubc.ca/larajung/
* Erica Wong http://blogs.ubc.ca/ericawong/
* Frances Langtry http://blogs.ubc.ca/franceslangtry/
* Rebecca Kenward https://blogs.ubc.ca/rebeccakenward/
* Amie Kim http://blogs.ubc.ca/amiekim/

GROUP 2
* Apollina Kyle https://blogs.ubc.ca/pollykyle/
* Keely Yu http://blogs.ubc.ca/keelyyu/
* Nicole Jackson http://blogs.ubc.ca/nicolejsblog/
* Suanne Lau http://blogs.ubc.ca/suanne/
* Geneva Gordon http://blogs.ubc.ca/genevagordon/
* Carlene Loughlin http://blogs.ubc.ca/carlenegrsj/
* Lauryn Collins http://blogs.ubc.ca/lcollinsgrsj/2017/06/30/fashion-ing-the-notion-of-women-in-their-place/
* Rebecca Li http://blogs.ubc.ca/grsj300rebeccaliculturejam/
* Isha Jain http://blogs.ubc.ca/ishajaingrsj/

GROUP 3
*Hayley Jim http://blogs.ubc.ca/hayleyjim/
*Cecile Ouillet http://blogs.ubc.ca/cecile/
*Vivian Guo http://blogs.ubc.ca/vivguo/
*Gabrielle Vecchio https://blogs.ubc.ca/gabriellevecchiogrsj300/
*Delaram "Del" Hajipour http://blogs.ubc.ca/delhajipour/
*Katelyn Roberts http://blogs.ubc.ca/katelynjoan/
*Tiffany Tang http://blogs.ubc.ca/tiffanytang/
*Peter Craigen http://blogs.ubc.ca/peterjc/

GROUP 4
* Emily Nawar https://blogs.ubc.ca/emilynawar/
* Jeff Lee http://blogs.ubc.ca/jefflee
* Sarah Neubauer http://blogs.ubc.ca/sarahneubauer/
* Lina Khairallah https://blogs.ubc.ca/linakhairallah/
* Keiko Pan http://blogs.ubc.ca/keikopan/
* Rachel Burns http://blogs.ubc.ca/rachelburns
* Erin Wallace http://blogs.ubc.ca/erinwallace/2017/06/30/grsj-300-culture-jam-clorox-and-rosie-the-riveter/
* Marina Tischenko https://blogs.ubc.ca/marinatnko/
* Gurveen Dhaliwal http://blogs.ubc.ca/gurveendhaliwal/

GROUP 5
* Brett Shearing http://blogs.ubc.ca/brettshearing/
* Nunu King http://blogs.ubc.ca/nunuking/
* Kelsey Driessen http://blogs.ubc.ca/kelseydriessen/
* Carmen Chow https://blogs.ubc.ca/carmenchow/
* AnQi Suo http://blogs.ubc.ca/anqisuo/
* Iris Law http://blogs.ubc.ca/irislaw/
*Christie Ong http://blogs.ubc.ca/christieong/
*Don Fazl https://blogs.ubc.ca/donfazlgrsj300/
*Nitzan Ziv https://blogs.ubc.ca/nitzanziv1/wp-admin/post.php?post=1&action=edit
*Shahla Abdolkarim Ali http://blogs.ubc.ca/shahlaali85/

GROUP 6
*Christine Ganase http://blogs.ubc.ca/cjganase/
*Lizzy Ojo http://blogs.ubc.ca/culturejambylizzyojo/
*Claire Livingstone http://blogs.ubc.ca/clairelivingstone
*Andrew Ting http://blogs.ubc.ca/andrewting/
*Aleea Dahinden http://blogs.ubc.ca/dahinden/2017/06/30/jammed-ad-grsj-300/
*Amy Alexandrian http://blogs.ubc.ca/amyalexandrian/
*Ann Dinh https://blogs.ubc.ca/adinny/
* Zainab Ahmed https://blogs.ubc.ca/zainabahmed
* Ali Hussein https://blogs.ubc.ca/aliihussein

GROUP 7
*Yi Xiong https://blogs.ubc.ca/yixiong/?p=8&preview=true
* Chanel Trac http://blogs.ubc.ca/chaneltrac/
* Bryleigh Leblanc-Wong http://blogs.ubc.ca/bryleighw/
* Ben Etkin-Goulet http://blogs.ubc.ca/etkingouletben/
* Miranda Choo http://blogs.ubc.ca/mirandagrsj300/
* Jessica Liang http://blogs.ubc.ca/jessicaliang/
* Jennifer McDermid: https://blogs.ubc.ca/jennmcdermid/
* Joan Canave https://blogs.ubc.ca/joancanave/
*Jiven Bal http://blogs.ubc.ca/jivenbal

=== 2016WC-GRSJ300-99C (Instructor: Dr. Manjeet Birk)===

GROUP 1
*Brooke Manchester http://blogs.ubc.ca/brookemanchester
* Salice Kale http://blogs.ubc.ca/salicek/
*Larissa Goh http://blogs.ubc.ca/larissag/
*Ivy Debinski http://blogs.ubc.ca/ivydebinski/
*Nathalie Egenaes http://blogs.ubc.ca/negenaesgrsj300/
* Tatyana Romeus-Kebe http://blogs.ubc.ca/tatyanaromeuskebe/
*Sara Fahlander http://blogs.ubc.ca/sarafahlander/
*Agatha Widjaja https://blogs.ubc.ca/agathawidjaja/
*Cormac O'Dwyer http://blogs.ubc.ca/cormacodwyer/
*Julie Li http://blogs.ubc.ca/julieli/
*Lee Nagy http://blogs.ubc.ca/leenagy/
*Grace Riddell http://blogs.ubc.ca/graceriddell/

GROUP 2
* Charmaine Magday https://blogs.ubc.ca/magdayc
* Kim Nguyen https://blogs.ubc.ca/kimnguyen
* Hayley Lyons http://blogs.ubc.ca/hayleylyons/
* Nicole Lam http://blogs.ubc.ca/nicolelam/
* Melissa Chinaloy http://blogs.ubc.ca/melchinaloy
* Danielle Dickson http://blogs.ubc.ca/dicda/
* Kumar Rithvik Kasireddy http://blogs.ubc.ca/kumarrithvikkasireddy/
* Alaina Chun http://blogs.ubc.ca/alainachungrsj300/
* Julia Hofmann http://blogs.ubc.ca/juliaehofmann/grsj300/
* Cevina Ghuman http://blogs.ubc.ca/cevinaghuman/

GROUP 3
* Jacqueline Yan http://blogs.ubc.ca/jyan/
* Katina Nguyen http://blogs.ubc.ca/katinanguyen/
* Chloe Hronopoulos http://blogs.ubc.ca/chloehronopouloss/
* Maddie Lafleur http://blogs.ubc.ca/maddielafleur/
*Justine Doiron http://blogs.ubc.ca/jdoiron/
* Stephanie Miflores http://blogs.ubc.ca/stephaniemiflores/
* Evan Kwong http://blogs.ubc.ca/eakwong/grsj-300/
* Rawan Mokabel http://blogs.ubc.ca/rawanm/2017/02/21/culture-jam-assignment/
* Miranda Gibson http://blogs.ubc.ca/mirandagibson/culture-jam-assignment/
GROUP 4
* Jordyn Shaw https://blogs.ubc.ca/jordynshaw/
*Jeannette Zheng https://blogs.ubc.ca/jeannettezheng/
* Abdulellah Altayar http://blogs.ubc.ca/abdulellahaltayar/
* Amanpreet Sidhu http://blogs.ubc.ca/amansidhu/
* Annie Choi http://blogs.ubc.ca/anniechoigrsj300
* Parmvir Brar http://blogs.ubc.ca/parmvirbrar/
* Ethan Schnell http://blogs.ubc.ca/ethanschnell/2017/02/16/
* David Rallis http://blogs.ubc.ca/davidrallis/
*Kini Tao http://blogs.ubc.ca/kinitao/
*Marissa Upshaw http://blogs.ubc.ca/mupshaw/

GROUP 5
*Aanchal Puri http://blogs.ubc.ca/aanchalpuri/
*Jomar Santos https://blogs.ubc.ca/jomarsantos
*Leah Walden http://blogs.ubc.ca/leahwalden
*Morgan Lyon http://blogs.ubc.ca/morganlyon/
* Lal Koyuncu http://blogs.ubc.ca/lalkoyuncu
* Sara Lisk http://blogs.ubc.ca/saralisk/
* Angela Bradshaw http://blogs.ubc.ca/angelabradshaw/
*Amanda Lee http://blogs.ubc.ca/amandatclee
*Terrisa Inthapanya http://blogs.ubc.ca/terrisainthapanya/

GROUP 6
*Adeline Hao https://blogs.ubc.ca/adelinehao
*Adrian Dizon http://blogs.ubc.ca/adriandizongrsj300/
*Gurjot Singh http://blogs.ubc.ca/gurjotsingh
*Stacey Forrester http://blogs.ubc.ca/staceyforrester/
*Khaleed Mawji https://blogs.ubc.ca/khaleedmawji/
*Delainey Lockett http://blogs.ubc.ca/delaineylockett/
*Jessica Liu http://blogs.ubc.ca/jessicaliu300/
*Chantel Jackson http://blogs.ubc.ca/chanteljackson/
*James Macklem http://blogs.ubc.ca/jamiemacklem/2017/02/17/culture-jam/
*Bharvita Nakum http://blogs.ubc.ca/bharvitanakum/

GROUP 7
*Jocelyn Gould http://blogs.ubc.ca/jocelyngouldgrsj300/
*Kieran Bath http://blogs.ubc.ca/kieranbathgrsj
*Matthew Ward http://blogs.ubc.ca/matthewjward/
*Michelle Blaine http://blogs.ubc.ca/michelleblaine/
*Erik Matson http://blogs.ubc.ca/erikmatson/
*Brooke Lynch http://blogs.ubc.ca/brookelynch/
*Elizabeth Huston-Herterich http://blogs.ubc.ca/elizabethhustonherterich/
*Samantha Martin-Ferris https://blogs.ubc.ca/fnis410samantha/
*Tammy Chou http://blogs.ubc.ca/tammychou/
*Ella Klein http://blogs.ubc.ca/ellaklein/
*Kashtin De Souza http://blogs.ubc.ca/coronabeer/corona-extra/
*Jeongeun (Ellen) Lee http://blogs.ubc.ca/imellen/
*[Megan][Bethune] : http://blogs.ubc.ca/meganbethune/2017/03/29/hello-world//blogurl 
*Jennifer McDermid: https://blogs.ubc.ca/jennmcdermid/
*Jiven Bal: http://blogs.ubc.ca/jivenbal/2017/06/30/original-ad/

=== 2016WA-GRSJ300-99A (Instructor: Dr. Chris Shelley)===
*Sidra Baig http://blogs.ubc.ca/sidrab/
*Natasha Mutombe http://blogs.ubc.ca/natashafadzayi/
*Colin May http://blogs.ubc.ca/trumpdump/2016/10/21/culture-jam-assignment-politics-on-the-home-front/
*Gary Teng http://blogs.ubc.ca/gtengyy/
*Manni Xiao http://blogs.ubc.ca/mannixiao/
* Kaitlyn Guzman http://blogs.ubc.ca/kaitlynguzman/
* Ksenia Stepkina https://blogs.ubc.ca/kseniastepkina/
* Ali Hodroje http://blogs.ubc.ca/ahodr/
*Erica Yang http://blogs.ubc.ca/ericayang/
* Naomy Kang http://blogs.ubc.ca/naomykang/
*Jin Roh http://blogs.ubc.ca/jinroh/
* Veronika Zaytseva http://blogs.ubc.ca/veronikazayts/
* Clarissa Lau http://blogs.ubc.ca/clarissalau/
* Christina Hebert http://blogs.ubc.ca/christinahebert/
* Tania Jagpal http://blogs.ubc.ca/taniajagpal/
* Paige Knights http://blogs.ubc.ca/paigeknights
* Chloë Parkin http://blogs.ubc.ca/chloehcparkin/
* Sheila Low http://blogs.ubc.ca/sheilalow/
* Samantha Smirfitt https://blogs.ubc.ca/samantha300
* Natalie Boag http://blogs.ubc.ca/natalieboag/
* Erin Thomas http://blogs.ubc.ca/erinthomas/
*Mackenzie Stevens http://blogs.ubc.ca/mackenziestevens/
* Madeleine Luke http://blogs.ubc.ca/madeleineluke2/
* Maria Rakina http://blogs.ubc.ca/mariarakina/
* Abirami Muthukumar http://blogs.ubc.ca/amuthukumar/
* Natalie Amoore http://blogs.ubc.ca/natalieamoore/
* Tiffany Koo http://blogs.ubc.ca/tiffanykoo/
* Kelly Taverner http://blogs.ubc.ca/kellytav/
* Pui Yu Emily Wong http://blogs.ubc.ca/emilywongg/
* Sisi Guo http://blogs.ubc.ca/sisiguo/
* Will Molloy http://blogs.ubc.ca/willmolloy/
* Kate Bezugley http://blogs.ubc.ca/katebezugley/
* Brogan Whatley http://blogs.ubc.ca/broganwhatley/
* Sarah May http://blogs.ubc.ca/sarahmay/
* Adan Barclay https://blogs.ubc.ca/adanbarclay/
* Quinn Dhaliwal http://blogs.ubc.ca/quinndhaliwal/
* Ava Mokhtari Fard http://blogs.ubc.ca/ava123
* Christine Ma http://blogs.ubc.ca/grsj300christinema/
* Winston Limanto http://blogs.ubc.ca/winstonlimanto/
* Shay Prasad http://blogs.ubc.ca/shayprasad
* Arisha Shory http://blogs.ubc.ca/arishashory/
*Patrick Munyurangabo http://blogs.ubc.ca/patrickmu/
* Madeline Martin http://blogs.ubc.ca/madelinemartin/
* Ili Yang http://blogs.ubc.ca/iliyang/
* Maui Calleja http://blogs.ubc.ca/mcalleja/
* Najla Sekariyanti http://blogs.ubc.ca/najlasekar/
* Sherry Cheng http://blogs.ubc.ca/sherrycheng/
* Olivia Kam http://blogs.ubc.ca/oliviakam/
* Eliana Horvath http://blogs.ubc.ca/elianahorvath/
* Maelle Grenier http://blogs.ubc.ca/maellegrenier/
* Breanna Bernard http://blogs.ubc.ca/breannabernard/
* Chi-Han Lee http://blogs.ubc.ca/hanklee/
* Heather Farrell http://blogs.ubc.ca/heatherfarrell/'
* Tiffany Tsang http://blogs.ubc.ca/tsang007/
* Olivia Lo http://blogs.ubc.ca/olivialo/
* Yeree (Kelly) Oh http://blogs.ubc.ca/kellyoh90
* Miranda Maxwell http://blogs.ubc.ca/grsj300culturaljammingmmaxwell/1-2/
*Ciara Dushnisky http://blogs.ubc.ca/ciaradushnisky/
*Monique Beaulieu http://blogs.ubc.ca/moniquebeaulieu/
*Zhi Hao Wan http://blogs.ubc.ca/zhihaowan/
*Emily Zaporozan http://blogs.ubc.ca/grsj300emilyzap/
*Amanda Burns http://blogs.ubc.ca/amandaburns/
* Yunxia Lin http://blogs.ubc.ca/yunxia/
* Cindy Wang http://blogs.ubc.ca/cndyy/
* Hannah Wagner [https://blogs.ubc.ca/hannahw/ GRSJ 300 Blog]
* Colin May http://blogs.ubc.ca/trumpdump
*Imaan Punja http://blogs.ubc.ca/imaanpunja/2016/10/21/victorias-secret-double-standard/
* Sebastian Silley http://blogs.ubc.ca/silleysebastian/
*Yumi Chang http://blogs.ubc.ca/yumichang/

=== 2016SA-GRSJ300-98A (Instructor: Dr. Ray Hsu)===
*Ishita Ashraf http://blogs.ubc.ca/ashrafishita
*Michelle Leung http://blogs.ubc.ca/michellewmleung/
*Eyvette Runner http://blogs.ubc.ca/eyvetterunner/2016/06/24/gsnj300-culture-jam-2016/
*Zi Qi Xu (May) http://blogs.ubc.ca/ziqixu/
*Karen Xingyu Gu http://blogs.ubc.ca/karengu/
*Varuntorn Kiatyudhachart http://blogs.ubc.ca/varuntornk/
*Stephanie Armstrong http://blogs.ubc.ca/stephaniearmstrong/
*Ryan Crosschild https://blogs.ubc.ca/ryanpcrosschild/
*Taya Henry http://blogs.ubc.ca/tayahenryubc/ 
*Courtney Kelly http://blogs.ubc.ca/courtneykelly/2016/06/23/peta/
*Karilynne Davies https://blogs.ubc.ca/karilynnedavies/
*Madisen Butterfield http://blogs.ubc.ca/madisenbutterfield/
*Lyzina Mondiwa //http://blogs.ubc.ca/lyzinamondiwa/ 
*Angela Chia https://blogs.ubc.ca/grsj300angelachia/
*Deprice Martens http://blogs.ubc.ca/depricemartens/
*Tokey Xiao http://blogs.ubc.ca/tuoxiao/
*Heather James http://blogs.ubc.ca/heatherjames/
*Joey Manaligod http://blogs.ubc.ca/joeymanaligod/
*Kendra Parkinson http://blogs.ubc.ca/kendraparkinson/
*Heather Baker http://blogs.ubc.ca/heatherbaker/
*Lauren Cheng http://blogs.ubc.ca/laurencheng/
*Katja Volz http://blogs.ubc.ca/katjavolz/
*Mackenzie Lee http://blogs.ubc.ca/mackenzielee/
*Lian Xue http://blogs.ubc.ca/xuelian/
*Lauren Slattery http://blogs.ubc.ca/laurenslatterygrsj/
*May Lum http://blogs.ubc.ca/maylum/
*Shoukia van Beek http://blogs.ubc.ca/shoukia/
*Julie (Seoyeon) Jung http://blogs.ubc.ca/juliejung/
*Jalini Paramsothi http://blogs.ubc.ca/Jaliniparamsothi/
*Monica Cygan http://blogs.ubc.ca/monicacygan/
*Alice Jin (Sheng Hui) http://blogs.ubc.ca/shenghuijin/
*Lucas Kling http://blogs.ubc.ca/lucaskling
*Tania Talebzadeh http://blogs.ubc.ca/taniataleb/
*Holly Shodin http://blogs.ubc.ca/hshodin/
*Priya Painuly http://blogs.ubc.ca/priyapainuly/
*Eileen Ruan http://blogs.ubc.ca/eileenruan/
*Yi Zhou http://blogs.ubc.ca/yizhou/
*Xinyu Wang http://blogs.ubc.ca/xinyuwang322/
*Erin Cederberg http://blogs.ubc.ca/grsj300erinced/
*Alyssa Ready http://blogs.ubc.ca/readyalyssa/2016/06/22/culture-jam-assignment/
*Chantelle Fromager http://blogs.ubc.ca/chantellefromager/
*Celena Tan http://blogs.ubc.ca/maciltan/
*Bailey Fan http://blogs.ubc.ca/baileycfan/
*Alexis Zimmer http://blogs.ubc.ca/alexiszimmer/
*Ming Shi http://blogs.ubc.ca/mingshi/
*Mengyao Jia http://blogs.ubc.ca/mengyaojia
*Christine Shin http://blogs.ubc.ca/christneshin/
*Zackary Uganec http://blogs.ubc.ca/zuganec/
*Andrew Antes http://blogs.ubc.ca/andrewantes/2016/06/24/culture-jam-project-aunt-jemima-ad/
*Gillian Guest http://blogs.ubc.ca/grsj300gguest/
*Sahib Dhaliwal http://blogs.ubc.ca/sahibdhaliwal/
*Colleen Fish https://blogs.ubc.ca/colleenfish/
*Nicole Yu http://blogs.ubc.ca/nicoyu/
*Syed Daniyal Shah http://blogs.ubc.ca/daniyalshah/
*Andy Holmes http://blogs.ubc.ca/andyholmes/
*Stephanie Smith http://blogs.ubc.ca/smithculturejam300/
*Chloe Johnstone http://blogs.ubc.ca/chloejohnstone/
*Kelsey Walker http://blogs.ubc.ca/kelseywalker/
*Farbod Feizi http://blogs.ubc.ca/farbodfeizi/
*Madeline Martin http://http://blogs.ubc.ca/madelinemartin/
*Gabrielle Vecchio https://blogs.ubc.ca/gabriellevecchiogrsj300/

=== 2015WC-GRSJ300-99C (Instructor: Dr. Ray Hsu) ===

* Angela Fu http://blogs.ubc.ca/angelaf/
* Hailie He https://blogs.ubc.ca/hailiehe
* Sydney Harrison http://blogs.ubc.ca/sydneyharrison
* Carol Fan http://blogs.ubc.ca/carolfan
* Quinnie Sin http://blogs.ubc.ca/quinniesin
* Rainbow Ran http://blogs.ubc.ca/rainbowran/
* Ava Chan http://blogs.ubc.ca/avachan
* Jarvis Wong http://blogs.ubc.ca/jarviswong
* Cindy Fan https://blogs.ubc.ca/cindyfan
* Minkyo Kim http://blogs.ubc.ca/minkyokim
* Marcelle Tsoi http://blogs.ubc.ca/marcelletsoi
* Jiangui Ma http://blogs.ubc.ca/nickma
* Lawson Parker http://blogs.ubc.ca/lawsonpgrsj300/
* Summer Roddick http://blogs.ubc.ca/summerroddick
* Ivona Ognjanova: http://blogs.ubc.ca/ivonaognjanova/
* Chelsea Ellacott http://blogs.ubc.ca/chelseaellacott
* Jina Jeong http://blogs.ubc.ca/jinajeong/
* Anson Wong http://blogs.ubc.ca/ansonwong/
* Leilani Rodrigues http://blogs.ubc.ca/leilanirodrigues/
* Nabil Boschman http://blogs.ubc.ca/nabilgrsj/
* Vicky Gu http://blogs.ubc.ca/vickygu/
* Christy Grenon http://blogs.ubc.ca/christygrenon
* Quinne Mason http://blogs.ubc.ca/quinnemason
* Hannah Vaartnou http://blogs.ubc.ca/hannahev/
* Kelsey Clarke http://blogs.ubc.ca/kelseyclarke/
* Caira Jillian Sy http://blogs.ubc.ca/cairasy/
* Chloe Chong http://blogs.ubc.ca/chloechong/
* Angela Ho http://blogs.ubc.ca/grsj300angelaho/
* Jenee Penn http://blogs.ubc.ca/jeneepenn/
* Songling Yu http://blogs.ubc.ca/songlingyu/
* Caitlyn Simmons http://blogs.ubc.ca/caitlynsimmons/
* Melissa Wu http://blogs.ubc.ca/melissasywu/
* Jordan Williams-Yuen http://blogs.ubc.ca/jwilliamsyuen/
* Megan Miller http://blogs.ubc.ca/meganmiller/
* Robert Choate http://blogs.ubc.ca/robertchoate/
* Levana Huang http://blogs.ubc.ca/levanahuang/
* Charlotte Coilan http://blogs.ubc.ca/charlottecgrsj/
* Lilian Tseng https://blogs.ubc.ca/liliantsengblog/
* Liam Murphy-Burke http://blogs.ubc.ca/lmurphyburke/
* Karsten Leitner http://blogs.ubc.ca/karstenleitner/
* Kirisana Sivakumaran http://blogs.ubc.ca/kirisanasivakumaran/
* Katherine Smith http://blogs.ubc.ca/katherinesmith/
* Braden Fong http://blogs.ubc.ca/bradenfong430/
* John Kevin Chan http://blogs.ubc.ca/johnkevindelacruzchan/
* Jenoa Rabinovitch http://blogs.ubc.ca/jenoarabinovitch/
* Sum Lo http://blogs.ubc.ca/sumlo/
* Ben Tettamanti http://blogs.ubc.ca/bentettamanti/
* Chui Man Leung http://blogs.ubc.ca/chuimanleung/
* Samantha Peng http://blogs.ubc.ca/samanthapeng/
* ManLing Ngan http://blogs.ubc.ca/grsj300manlingngan
* Nick Ma http://blogs.ubc.ca/nickma/
* Jacqueline Dorsch http://blogs.ubc.ca/jacquelinedorsch/
* Eugene Park http://blogs.ubc.ca/eugenepark/
* Xinyu (Maggie) Li http://blogs.ubc.ca/grsj300xinyuli/2016/04/08/video-mashup-assignment/
* Sandy Marji http://blogs.ubc.ca/sandymarji/
* Brandon Pearl http://blogs.ubc.ca/brandonpearlgrsj300/
* Szascha Lim http://blogs.ubc.ca/szaschalimgrsj300/
* Melissa Siy http://blogs.ubc.ca/melissasiygrsj/
* Sofia Kim http://blogs.ubc.ca/hungrynotlean/
* Alex Bain http://blogs.ubc.ca/grsj300abain/
* Aidan Gregory http://blogs.ubc.ca/aidangregory/2016/04/08/the-progress-of-feminism-mashup/
*Samantha Solomon http://http://blogs.ubc.ca/samanthasolomon/
*Crystal Yee http://blogs.ubc.ca/crystalyee/
*Coraline Félix http://blogs.ubc.ca/coralinefelix/
*Torey White http://blogs.ubc.ca/toreywhite/
*Yasaman Fazel http://blogs.ubc.ca/yfazelm/culture-jam-assignment/
*Jennifer McDermid: https://blogs.ubc.ca/jennmcdermid/
*Jiven Bal http://blogs.ubc.ca/jivenbal
*Zohra Moshtaq http://blogs.ubc.ca/zohramoshtaq/

GRSJ300StudentBlogs

2017-08-24T21:06:59Z

AliHussein:

Post your UBC Blog URLS here! Please follow the following format: [Firstname] [Lastname] http://blogs.ubc.ca/blogurl 
Note: use '''http://''', do not use https://

=== 2017SA-GRSJ300-98A (Instructor: Dr. Ray Hsu)===

GROUP 1
* Kate (Kathryn) McLaughlin https://blogs.ubc.ca/kathrynmcl/
* Qi Mao http://blogs.ubc.ca/qimao
* Ashley Hayes http://blogs.ubc.ca/ashleyhayes
* Sarah Siska http://blogs.ubc.ca/sarahsiska/
* Angelina Sung http://blogs.ubc.ca/angelinasung/2017/06/27/angelinasung/
* Lara Jung http://blogs.ubc.ca/larajung/
* Erica Wong http://blogs.ubc.ca/ericawong/
* Frances Langtry http://blogs.ubc.ca/franceslangtry/
* Rebecca Kenward https://blogs.ubc.ca/rebeccakenward/
* Amie Kim http://blogs.ubc.ca/amiekim/

GROUP 2
* Apollina Kyle https://blogs.ubc.ca/pollykyle/
* Keely Yu http://blogs.ubc.ca/keelyyu/
* Nicole Jackson http://blogs.ubc.ca/nicolejsblog/
* Suanne Lau http://blogs.ubc.ca/suanne/
* Geneva Gordon http://blogs.ubc.ca/genevagordon/
* Carlene Loughlin http://blogs.ubc.ca/carlenegrsj/
* Lauryn Collins http://blogs.ubc.ca/lcollinsgrsj/2017/06/30/fashion-ing-the-notion-of-women-in-their-place/
* Rebecca Li http://blogs.ubc.ca/grsj300rebeccaliculturejam/
* Isha Jain http://blogs.ubc.ca/ishajaingrsj/

GROUP 3
*Hayley Jim http://blogs.ubc.ca/hayleyjim/
*Cecile Ouillet http://blogs.ubc.ca/cecile/
*Vivian Guo http://blogs.ubc.ca/vivguo/
*Gabrielle Vecchio https://blogs.ubc.ca/gabriellevecchiogrsj300/
*Delaram "Del" Hajipour http://blogs.ubc.ca/delhajipour/
*Katelyn Roberts http://blogs.ubc.ca/katelynjoan/
*Tiffany Tang http://blogs.ubc.ca/tiffanytang/
*Peter Craigen http://blogs.ubc.ca/peterjc/

GROUP 4
* Emily Nawar https://blogs.ubc.ca/emilynawar/
* Jeff Lee http://blogs.ubc.ca/jefflee
* Sarah Neubauer http://blogs.ubc.ca/sarahneubauer/
* Lina Khairallah https://blogs.ubc.ca/linakhairallah/
* Keiko Pan http://blogs.ubc.ca/keikopan/
* Rachel Burns http://blogs.ubc.ca/rachelburns
* Erin Wallace http://blogs.ubc.ca/erinwallace/2017/06/30/grsj-300-culture-jam-clorox-and-rosie-the-riveter/
* Marina Tischenko https://blogs.ubc.ca/marinatnko/
* Gurveen Dhaliwal http://blogs.ubc.ca/gurveendhaliwal/

GROUP 5
* Brett Shearing http://blogs.ubc.ca/brettshearing/
* Nunu King http://blogs.ubc.ca/nunuking/
* Kelsey Driessen http://blogs.ubc.ca/kelseydriessen/
* Carmen Chow https://blogs.ubc.ca/carmenchow/
* AnQi Suo http://blogs.ubc.ca/anqisuo/
* Iris Law http://blogs.ubc.ca/irislaw/
*Christie Ong http://blogs.ubc.ca/christieong/
*Don Fazl https://blogs.ubc.ca/donfazlgrsj300/
*Nitzan Ziv https://blogs.ubc.ca/nitzanziv1/wp-admin/post.php?post=1&action=edit
*Shahla Abdolkarim Ali http://blogs.ubc.ca/shahlaali85/

GROUP 6
*Christine Ganase http://blogs.ubc.ca/cjganase/
*Lizzy Ojo http://blogs.ubc.ca/culturejambylizzyojo/
*Claire Livingstone http://blogs.ubc.ca/clairelivingstone
*Andrew Ting http://blogs.ubc.ca/andrewting/
*Aleea Dahinden http://blogs.ubc.ca/dahinden/2017/06/30/jammed-ad-grsj-300/
*Amy Alexandrian http://blogs.ubc.ca/amyalexandrian/
*Ann Dinh https://blogs.ubc.ca/adinny/
* Zainab Ahmed https://blogs.ubc.ca/zainabahmed
* Ali Hussein https://blogs.ubc.ca/alihussein

GROUP 7
*Yi Xiong https://blogs.ubc.ca/yixiong/?p=8&preview=true
* Chanel Trac http://blogs.ubc.ca/chaneltrac/
* Bryleigh Leblanc-Wong http://blogs.ubc.ca/bryleighw/
* Ben Etkin-Goulet http://blogs.ubc.ca/etkingouletben/
* Miranda Choo http://blogs.ubc.ca/mirandagrsj300/
* Jessica Liang http://blogs.ubc.ca/jessicaliang/
* Jennifer McDermid: https://blogs.ubc.ca/jennmcdermid/
* Joan Canave https://blogs.ubc.ca/joancanave/
*Jiven Bal http://blogs.ubc.ca/jivenbal

=== 2016WC-GRSJ300-99C (Instructor: Dr. Manjeet Birk)===

GROUP 1
*Brooke Manchester http://blogs.ubc.ca/brookemanchester
* Salice Kale http://blogs.ubc.ca/salicek/
*Larissa Goh http://blogs.ubc.ca/larissag/
*Ivy Debinski http://blogs.ubc.ca/ivydebinski/
*Nathalie Egenaes http://blogs.ubc.ca/negenaesgrsj300/
* Tatyana Romeus-Kebe http://blogs.ubc.ca/tatyanaromeuskebe/
*Sara Fahlander http://blogs.ubc.ca/sarafahlander/
*Agatha Widjaja https://blogs.ubc.ca/agathawidjaja/
*Cormac O'Dwyer http://blogs.ubc.ca/cormacodwyer/
*Julie Li http://blogs.ubc.ca/julieli/
*Lee Nagy http://blogs.ubc.ca/leenagy/
*Grace Riddell http://blogs.ubc.ca/graceriddell/

GROUP 2
* Charmaine Magday https://blogs.ubc.ca/magdayc
* Kim Nguyen https://blogs.ubc.ca/kimnguyen
* Hayley Lyons http://blogs.ubc.ca/hayleylyons/
* Nicole Lam http://blogs.ubc.ca/nicolelam/
* Melissa Chinaloy http://blogs.ubc.ca/melchinaloy
* Danielle Dickson http://blogs.ubc.ca/dicda/
* Kumar Rithvik Kasireddy http://blogs.ubc.ca/kumarrithvikkasireddy/
* Alaina Chun http://blogs.ubc.ca/alainachungrsj300/
* Julia Hofmann http://blogs.ubc.ca/juliaehofmann/grsj300/
* Cevina Ghuman http://blogs.ubc.ca/cevinaghuman/

GROUP 3
* Jacqueline Yan http://blogs.ubc.ca/jyan/
* Katina Nguyen http://blogs.ubc.ca/katinanguyen/
* Chloe Hronopoulos http://blogs.ubc.ca/chloehronopouloss/
* Maddie Lafleur http://blogs.ubc.ca/maddielafleur/
*Justine Doiron http://blogs.ubc.ca/jdoiron/
* Stephanie Miflores http://blogs.ubc.ca/stephaniemiflores/
* Evan Kwong http://blogs.ubc.ca/eakwong/grsj-300/
* Rawan Mokabel http://blogs.ubc.ca/rawanm/2017/02/21/culture-jam-assignment/
* Miranda Gibson http://blogs.ubc.ca/mirandagibson/culture-jam-assignment/
GROUP 4
* Jordyn Shaw https://blogs.ubc.ca/jordynshaw/
*Jeannette Zheng https://blogs.ubc.ca/jeannettezheng/
* Abdulellah Altayar http://blogs.ubc.ca/abdulellahaltayar/
* Amanpreet Sidhu http://blogs.ubc.ca/amansidhu/
* Annie Choi http://blogs.ubc.ca/anniechoigrsj300
* Parmvir Brar http://blogs.ubc.ca/parmvirbrar/
* Ethan Schnell http://blogs.ubc.ca/ethanschnell/2017/02/16/
* David Rallis http://blogs.ubc.ca/davidrallis/
*Kini Tao http://blogs.ubc.ca/kinitao/
*Marissa Upshaw http://blogs.ubc.ca/mupshaw/

GROUP 5
*Aanchal Puri http://blogs.ubc.ca/aanchalpuri/
*Jomar Santos https://blogs.ubc.ca/jomarsantos
*Leah Walden http://blogs.ubc.ca/leahwalden
*Morgan Lyon http://blogs.ubc.ca/morganlyon/
* Lal Koyuncu http://blogs.ubc.ca/lalkoyuncu
* Sara Lisk http://blogs.ubc.ca/saralisk/
* Angela Bradshaw http://blogs.ubc.ca/angelabradshaw/
*Amanda Lee http://blogs.ubc.ca/amandatclee
*Terrisa Inthapanya http://blogs.ubc.ca/terrisainthapanya/

GROUP 6
*Adeline Hao https://blogs.ubc.ca/adelinehao
*Adrian Dizon http://blogs.ubc.ca/adriandizongrsj300/
*Gurjot Singh http://blogs.ubc.ca/gurjotsingh
*Stacey Forrester http://blogs.ubc.ca/staceyforrester/
*Khaleed Mawji https://blogs.ubc.ca/khaleedmawji/
*Delainey Lockett http://blogs.ubc.ca/delaineylockett/
*Jessica Liu http://blogs.ubc.ca/jessicaliu300/
*Chantel Jackson http://blogs.ubc.ca/chanteljackson/
*James Macklem http://blogs.ubc.ca/jamiemacklem/2017/02/17/culture-jam/
*Bharvita Nakum http://blogs.ubc.ca/bharvitanakum/

GROUP 7
*Jocelyn Gould http://blogs.ubc.ca/jocelyngouldgrsj300/
*Kieran Bath http://blogs.ubc.ca/kieranbathgrsj
*Matthew Ward http://blogs.ubc.ca/matthewjward/
*Michelle Blaine http://blogs.ubc.ca/michelleblaine/
*Erik Matson http://blogs.ubc.ca/erikmatson/
*Brooke Lynch http://blogs.ubc.ca/brookelynch/
*Elizabeth Huston-Herterich http://blogs.ubc.ca/elizabethhustonherterich/
*Samantha Martin-Ferris https://blogs.ubc.ca/fnis410samantha/
*Tammy Chou http://blogs.ubc.ca/tammychou/
*Ella Klein http://blogs.ubc.ca/ellaklein/
*Kashtin De Souza http://blogs.ubc.ca/coronabeer/corona-extra/
*Jeongeun (Ellen) Lee http://blogs.ubc.ca/imellen/
*[Megan][Bethune] : http://blogs.ubc.ca/meganbethune/2017/03/29/hello-world//blogurl 
*Jennifer McDermid: https://blogs.ubc.ca/jennmcdermid/
*Jiven Bal: http://blogs.ubc.ca/jivenbal/2017/06/30/original-ad/

=== 2016WA-GRSJ300-99A (Instructor: Dr. Chris Shelley)===
*Sidra Baig http://blogs.ubc.ca/sidrab/
*Natasha Mutombe http://blogs.ubc.ca/natashafadzayi/
*Colin May http://blogs.ubc.ca/trumpdump/2016/10/21/culture-jam-assignment-politics-on-the-home-front/
*Gary Teng http://blogs.ubc.ca/gtengyy/
*Manni Xiao http://blogs.ubc.ca/mannixiao/
* Kaitlyn Guzman http://blogs.ubc.ca/kaitlynguzman/
* Ksenia Stepkina https://blogs.ubc.ca/kseniastepkina/
* Ali Hodroje http://blogs.ubc.ca/ahodr/
*Erica Yang http://blogs.ubc.ca/ericayang/
* Naomy Kang http://blogs.ubc.ca/naomykang/
*Jin Roh http://blogs.ubc.ca/jinroh/
* Veronika Zaytseva http://blogs.ubc.ca/veronikazayts/
* Clarissa Lau http://blogs.ubc.ca/clarissalau/
* Christina Hebert http://blogs.ubc.ca/christinahebert/
* Tania Jagpal http://blogs.ubc.ca/taniajagpal/
* Paige Knights http://blogs.ubc.ca/paigeknights
* Chloë Parkin http://blogs.ubc.ca/chloehcparkin/
* Sheila Low http://blogs.ubc.ca/sheilalow/
* Samantha Smirfitt https://blogs.ubc.ca/samantha300
* Natalie Boag http://blogs.ubc.ca/natalieboag/
* Erin Thomas http://blogs.ubc.ca/erinthomas/
*Mackenzie Stevens http://blogs.ubc.ca/mackenziestevens/
* Madeleine Luke http://blogs.ubc.ca/madeleineluke2/
* Maria Rakina http://blogs.ubc.ca/mariarakina/
* Abirami Muthukumar http://blogs.ubc.ca/amuthukumar/
* Natalie Amoore http://blogs.ubc.ca/natalieamoore/
* Tiffany Koo http://blogs.ubc.ca/tiffanykoo/
* Kelly Taverner http://blogs.ubc.ca/kellytav/
* Pui Yu Emily Wong http://blogs.ubc.ca/emilywongg/
* Sisi Guo http://blogs.ubc.ca/sisiguo/
* Will Molloy http://blogs.ubc.ca/willmolloy/
* Kate Bezugley http://blogs.ubc.ca/katebezugley/
* Brogan Whatley http://blogs.ubc.ca/broganwhatley/
* Sarah May http://blogs.ubc.ca/sarahmay/
* Adan Barclay https://blogs.ubc.ca/adanbarclay/
* Quinn Dhaliwal http://blogs.ubc.ca/quinndhaliwal/
* Ava Mokhtari Fard http://blogs.ubc.ca/ava123
* Christine Ma http://blogs.ubc.ca/grsj300christinema/
* Winston Limanto http://blogs.ubc.ca/winstonlimanto/
* Shay Prasad http://blogs.ubc.ca/shayprasad
* Arisha Shory http://blogs.ubc.ca/arishashory/
*Patrick Munyurangabo http://blogs.ubc.ca/patrickmu/
* Madeline Martin http://blogs.ubc.ca/madelinemartin/
* Ili Yang http://blogs.ubc.ca/iliyang/
* Maui Calleja http://blogs.ubc.ca/mcalleja/
* Najla Sekariyanti http://blogs.ubc.ca/najlasekar/
* Sherry Cheng http://blogs.ubc.ca/sherrycheng/
* Olivia Kam http://blogs.ubc.ca/oliviakam/
* Eliana Horvath http://blogs.ubc.ca/elianahorvath/
* Maelle Grenier http://blogs.ubc.ca/maellegrenier/
* Breanna Bernard http://blogs.ubc.ca/breannabernard/
* Chi-Han Lee http://blogs.ubc.ca/hanklee/
* Heather Farrell http://blogs.ubc.ca/heatherfarrell/'
* Tiffany Tsang http://blogs.ubc.ca/tsang007/
* Olivia Lo http://blogs.ubc.ca/olivialo/
* Yeree (Kelly) Oh http://blogs.ubc.ca/kellyoh90
* Miranda Maxwell http://blogs.ubc.ca/grsj300culturaljammingmmaxwell/1-2/
*Ciara Dushnisky http://blogs.ubc.ca/ciaradushnisky/
*Monique Beaulieu http://blogs.ubc.ca/moniquebeaulieu/
*Zhi Hao Wan http://blogs.ubc.ca/zhihaowan/
*Emily Zaporozan http://blogs.ubc.ca/grsj300emilyzap/
*Amanda Burns http://blogs.ubc.ca/amandaburns/
* Yunxia Lin http://blogs.ubc.ca/yunxia/
* Cindy Wang http://blogs.ubc.ca/cndyy/
* Hannah Wagner [https://blogs.ubc.ca/hannahw/ GRSJ 300 Blog]
* Colin May http://blogs.ubc.ca/trumpdump
*Imaan Punja http://blogs.ubc.ca/imaanpunja/2016/10/21/victorias-secret-double-standard/
* Sebastian Silley http://blogs.ubc.ca/silleysebastian/
*Yumi Chang http://blogs.ubc.ca/yumichang/

=== 2016SA-GRSJ300-98A (Instructor: Dr. Ray Hsu)===
*Ishita Ashraf http://blogs.ubc.ca/ashrafishita
*Michelle Leung http://blogs.ubc.ca/michellewmleung/
*Eyvette Runner http://blogs.ubc.ca/eyvetterunner/2016/06/24/gsnj300-culture-jam-2016/
*Zi Qi Xu (May) http://blogs.ubc.ca/ziqixu/
*Karen Xingyu Gu http://blogs.ubc.ca/karengu/
*Varuntorn Kiatyudhachart http://blogs.ubc.ca/varuntornk/
*Stephanie Armstrong http://blogs.ubc.ca/stephaniearmstrong/
*Ryan Crosschild https://blogs.ubc.ca/ryanpcrosschild/
*Taya Henry http://blogs.ubc.ca/tayahenryubc/ 
*Courtney Kelly http://blogs.ubc.ca/courtneykelly/2016/06/23/peta/
*Karilynne Davies https://blogs.ubc.ca/karilynnedavies/
*Madisen Butterfield http://blogs.ubc.ca/madisenbutterfield/
*Lyzina Mondiwa //http://blogs.ubc.ca/lyzinamondiwa/ 
*Angela Chia https://blogs.ubc.ca/grsj300angelachia/
*Deprice Martens http://blogs.ubc.ca/depricemartens/
*Tokey Xiao http://blogs.ubc.ca/tuoxiao/
*Heather James http://blogs.ubc.ca/heatherjames/
*Joey Manaligod http://blogs.ubc.ca/joeymanaligod/
*Kendra Parkinson http://blogs.ubc.ca/kendraparkinson/
*Heather Baker http://blogs.ubc.ca/heatherbaker/
*Lauren Cheng http://blogs.ubc.ca/laurencheng/
*Katja Volz http://blogs.ubc.ca/katjavolz/
*Mackenzie Lee http://blogs.ubc.ca/mackenzielee/
*Lian Xue http://blogs.ubc.ca/xuelian/
*Lauren Slattery http://blogs.ubc.ca/laurenslatterygrsj/
*May Lum http://blogs.ubc.ca/maylum/
*Shoukia van Beek http://blogs.ubc.ca/shoukia/
*Julie (Seoyeon) Jung http://blogs.ubc.ca/juliejung/
*Jalini Paramsothi http://blogs.ubc.ca/Jaliniparamsothi/
*Monica Cygan http://blogs.ubc.ca/monicacygan/
*Alice Jin (Sheng Hui) http://blogs.ubc.ca/shenghuijin/
*Lucas Kling http://blogs.ubc.ca/lucaskling
*Tania Talebzadeh http://blogs.ubc.ca/taniataleb/
*Holly Shodin http://blogs.ubc.ca/hshodin/
*Priya Painuly http://blogs.ubc.ca/priyapainuly/
*Eileen Ruan http://blogs.ubc.ca/eileenruan/
*Yi Zhou http://blogs.ubc.ca/yizhou/
*Xinyu Wang http://blogs.ubc.ca/xinyuwang322/
*Erin Cederberg http://blogs.ubc.ca/grsj300erinced/
*Alyssa Ready http://blogs.ubc.ca/readyalyssa/2016/06/22/culture-jam-assignment/
*Chantelle Fromager http://blogs.ubc.ca/chantellefromager/
*Celena Tan http://blogs.ubc.ca/maciltan/
*Bailey Fan http://blogs.ubc.ca/baileycfan/
*Alexis Zimmer http://blogs.ubc.ca/alexiszimmer/
*Ming Shi http://blogs.ubc.ca/mingshi/
*Mengyao Jia http://blogs.ubc.ca/mengyaojia
*Christine Shin http://blogs.ubc.ca/christneshin/
*Zackary Uganec http://blogs.ubc.ca/zuganec/
*Andrew Antes http://blogs.ubc.ca/andrewantes/2016/06/24/culture-jam-project-aunt-jemima-ad/
*Gillian Guest http://blogs.ubc.ca/grsj300gguest/
*Sahib Dhaliwal http://blogs.ubc.ca/sahibdhaliwal/
*Colleen Fish https://blogs.ubc.ca/colleenfish/
*Nicole Yu http://blogs.ubc.ca/nicoyu/
*Syed Daniyal Shah http://blogs.ubc.ca/daniyalshah/
*Andy Holmes http://blogs.ubc.ca/andyholmes/
*Stephanie Smith http://blogs.ubc.ca/smithculturejam300/
*Chloe Johnstone http://blogs.ubc.ca/chloejohnstone/
*Kelsey Walker http://blogs.ubc.ca/kelseywalker/
*Farbod Feizi http://blogs.ubc.ca/farbodfeizi/
*Madeline Martin http://http://blogs.ubc.ca/madelinemartin/
*Gabrielle Vecchio https://blogs.ubc.ca/gabriellevecchiogrsj300/

=== 2015WC-GRSJ300-99C (Instructor: Dr. Ray Hsu) ===

* Angela Fu http://blogs.ubc.ca/angelaf/
* Hailie He https://blogs.ubc.ca/hailiehe
* Sydney Harrison http://blogs.ubc.ca/sydneyharrison
* Carol Fan http://blogs.ubc.ca/carolfan
* Quinnie Sin http://blogs.ubc.ca/quinniesin
* Rainbow Ran http://blogs.ubc.ca/rainbowran/
* Ava Chan http://blogs.ubc.ca/avachan
* Jarvis Wong http://blogs.ubc.ca/jarviswong
* Cindy Fan https://blogs.ubc.ca/cindyfan
* Minkyo Kim http://blogs.ubc.ca/minkyokim
* Marcelle Tsoi http://blogs.ubc.ca/marcelletsoi
* Jiangui Ma http://blogs.ubc.ca/nickma
* Lawson Parker http://blogs.ubc.ca/lawsonpgrsj300/
* Summer Roddick http://blogs.ubc.ca/summerroddick
* Ivona Ognjanova: http://blogs.ubc.ca/ivonaognjanova/
* Chelsea Ellacott http://blogs.ubc.ca/chelseaellacott
* Jina Jeong http://blogs.ubc.ca/jinajeong/
* Anson Wong http://blogs.ubc.ca/ansonwong/
* Leilani Rodrigues http://blogs.ubc.ca/leilanirodrigues/
* Nabil Boschman http://blogs.ubc.ca/nabilgrsj/
* Vicky Gu http://blogs.ubc.ca/vickygu/
* Christy Grenon http://blogs.ubc.ca/christygrenon
* Quinne Mason http://blogs.ubc.ca/quinnemason
* Hannah Vaartnou http://blogs.ubc.ca/hannahev/
* Kelsey Clarke http://blogs.ubc.ca/kelseyclarke/
* Caira Jillian Sy http://blogs.ubc.ca/cairasy/
* Chloe Chong http://blogs.ubc.ca/chloechong/
* Angela Ho http://blogs.ubc.ca/grsj300angelaho/
* Jenee Penn http://blogs.ubc.ca/jeneepenn/
* Songling Yu http://blogs.ubc.ca/songlingyu/
* Caitlyn Simmons http://blogs.ubc.ca/caitlynsimmons/
* Melissa Wu http://blogs.ubc.ca/melissasywu/
* Jordan Williams-Yuen http://blogs.ubc.ca/jwilliamsyuen/
* Megan Miller http://blogs.ubc.ca/meganmiller/
* Robert Choate http://blogs.ubc.ca/robertchoate/
* Levana Huang http://blogs.ubc.ca/levanahuang/
* Charlotte Coilan http://blogs.ubc.ca/charlottecgrsj/
* Lilian Tseng https://blogs.ubc.ca/liliantsengblog/
* Liam Murphy-Burke http://blogs.ubc.ca/lmurphyburke/
* Karsten Leitner http://blogs.ubc.ca/karstenleitner/
* Kirisana Sivakumaran http://blogs.ubc.ca/kirisanasivakumaran/
* Katherine Smith http://blogs.ubc.ca/katherinesmith/
* Braden Fong http://blogs.ubc.ca/bradenfong430/
* John Kevin Chan http://blogs.ubc.ca/johnkevindelacruzchan/
* Jenoa Rabinovitch http://blogs.ubc.ca/jenoarabinovitch/
* Sum Lo http://blogs.ubc.ca/sumlo/
* Ben Tettamanti http://blogs.ubc.ca/bentettamanti/
* Chui Man Leung http://blogs.ubc.ca/chuimanleung/
* Samantha Peng http://blogs.ubc.ca/samanthapeng/
* ManLing Ngan http://blogs.ubc.ca/grsj300manlingngan
* Nick Ma http://blogs.ubc.ca/nickma/
* Jacqueline Dorsch http://blogs.ubc.ca/jacquelinedorsch/
* Eugene Park http://blogs.ubc.ca/eugenepark/
* Xinyu (Maggie) Li http://blogs.ubc.ca/grsj300xinyuli/2016/04/08/video-mashup-assignment/
* Sandy Marji http://blogs.ubc.ca/sandymarji/
* Brandon Pearl http://blogs.ubc.ca/brandonpearlgrsj300/
* Szascha Lim http://blogs.ubc.ca/szaschalimgrsj300/
* Melissa Siy http://blogs.ubc.ca/melissasiygrsj/
* Sofia Kim http://blogs.ubc.ca/hungrynotlean/
* Alex Bain http://blogs.ubc.ca/grsj300abain/
* Aidan Gregory http://blogs.ubc.ca/aidangregory/2016/04/08/the-progress-of-feminism-mashup/
*Samantha Solomon http://http://blogs.ubc.ca/samanthasolomon/
*Crystal Yee http://blogs.ubc.ca/crystalyee/
*Coraline Félix http://blogs.ubc.ca/coralinefelix/
*Torey White http://blogs.ubc.ca/toreywhite/
*Yasaman Fazel http://blogs.ubc.ca/yfazelm/culture-jam-assignment/
*Jennifer McDermid: https://blogs.ubc.ca/jennmcdermid/
*Jiven Bal http://blogs.ubc.ca/jivenbal
*Zohra Moshtaq http://blogs.ubc.ca/zohramoshtaq/

User:AliHussein

2011-01-28T07:58:36Z

AliHussein:

I'm just Alii, that is it!

Calculs is often used to solve economic problems in every days life. especially economic concepts concerning costs, profits and losses. forinstance if we look at the relationship between average cost and margianl cost. Marginal cost is the cost incured in producing an additional unit of a product. it is the cost per unit of a product as a gainst a total cost.it is therefore the variable cost of producing one more product of a unit whereas average cost is the average cost is the cost of production at an activity level. it is the total cost divided by the total production. when the average cost is less than the marginal cost MC>AC marginal cost pulls the average upward. when marginal cost is less than the average cost MC<AC marginal cost pulls the average cost downward. therefore im going to design an equation involved when margianl cost has no effect on average cost that is MC=AC. this is the point at which the marginal cost cuts the average cost at it's minimum.

Let us take Average cost as C/X and Marginal cost as dc/dx where c is the cost of the item and x is the number of items

Now:

d/dx[c(X)/x]=0

[xdc/dx-c(x)(1)]/x^2 =0

xdc/dx-c =0

xdc/dx =c

Therefore dc/dx = c/x which shows the relationship that MC = AV

User:AliHussein

2011-01-28T07:46:59Z

AliHussein:

I'm just Alii, that is it!

Calculs is often used to solve economic problems in every days life. especially economic concepts concerning costs, profits and losses. forinstance if we look at the relationship between average cost and margianl cost. when the average cost is less than the marginal cost MC>AC marginal cost pulls the average upward. when marginal cost is less than the average cost MC<AC marginal cost pulls the average cost downward. therefore im going to design an equation involved when margianl cost has no effect on average cost that is MC=AC. this is the point at which the marginal cost cuts the average cost at it's minimum.

Consider that:
Average cost = C/X
Marginal cost = dc/dx

Now: d/dx[c(X)/x]=0

[xdc/dx-c(x)(1)]/x^2 =0

xdc/dx-c =0

xdc/dx =c
therefore dc/dx = c/x which showas the relationship that MC = AV

Course:MATH110/Archive/2010-2011/003/Teams/Graubunden

2011-01-19T05:22:31Z

AliHussein:

{{
Infobox MATH110 Teams
| team name = Graubunden
| member 1 = Ali Abdi Hussein
| member 2 = Byron Godoy Pinzon
| member 3 = Derek Moore
| member 4 = [[User:JustineVallieres|JustineVallieres]]
}}
In workshop J.

'''Derek'''

mailto:fiveflip@interchange.ubc.ca

604.762.6133

'''Justine'''

mailto:justinevall18@hotmail.com

778.846.1808

ALII

aliiabdi@hotmail.com

604-720-3409

== Homework 11: Assignments ==

''Justine:''

The average cost remains constant as production increases.

Any other interesting properties that you can think of and create a model for. Bonus points can be obtained for very interesting ideas.

''Derek:''

Describe your model.

What does your model predict for a production of 150 items?

According to your model, what happens to the average cost per item as production levels increase

''Byron''

The average cost diminishes as production increases.

You obtain an economy of scale. This means that starting at some specific production level, the marginal cost is always less than the average cost.

''Ali''

The average cost increases as production increases.

the average cost first decreases as production increses, reaches a minimum and then increases as production continous to increase.

'''And when you get the chance, please post your contact info on the team page!'

== Homework 11 ==

[[Course:Math110/003/Teams/Graubunden/Homework 11|Homework 11 due Wednesday January 19]]

User:AliHussein

2011-01-19T03:55:13Z

AliHussein: Replaced content with "I'm Ali,"

I'm Ali,

Course:MATH110/Archive/2010-2011/003/Teams/Graubunden

2011-01-18T19:27:47Z

AliHussein:

{{
Infobox MATH110 Teams
| team name = Graubunden
| member 1 = Ali Abdi Hussein
| member 2 = Byron Godoy Pinzon
| member 3 = Derek Moore
| member 4 = [[User:JustineVallieres|JustineVallieres]]
}}
In workshop J.

'''Derek'''

mailto:fiveflip@interchange.ubc.ca

604.762.6133

'''Justine'''

mailto:justinevall18@hotmail.com

778.846.1808

ALII

aliiabdi@hotmail.com

604-720-3409

== Homework 11: Assignments ==

''Justine:''

The average cost remains constant as production increases.

Any other interesting properties that you can think of and create a model for. Bonus points can be obtained for very interesting ideas.

''Derek:''

Describe your model.

What does your model predict for a production of 150 items?

According to your model, what happens to the average cost per item as production levels increase

''Byron''

The average cost diminishes as production increases.

You obtain an economy of scale. This means that starting at some specific production level, the marginal cost is always less than the average cost.

''Ali''

The average cost increases as production increases.

'''And when you get the chance, please post your contact info on the team page!'''

== Homework 11 ==

[[Course:Math110/003/Teams/Graubunden/Homework 11|Homework 11 due Wednesday January 19]]

Course:MATH110/Archive/2010-2011/003/Teams/Graubunden

2011-01-13T08:36:54Z

AliHussein:

Infobox MATH110 Teams
| team name = Graubunden
| member 1 = Ali Abdi Hussein
| member 2 = Byron Godoy Pinzon
| member 3 = Derek Moore
| member 4 = [[User:JustineVallieres|JustineVallieres]]
}}
In workshop J.

Course:MATH110/Archive/2010-2011/003/Teams/Graubunden

2011-01-13T08:36:22Z

AliHussein:

I'm Alii.....{{
Infobox MATH110 Teams
| team name = Graubunden
| member 1 = Ali Abdi Hussein
| member 2 = Byron Godoy Pinzon
| member 3 = Derek Moore
| member 4 = [[User:JustineVallieres|JustineVallieres]]
}}
In workshop J.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09/Basic Skills Project

2010-12-01T05:06:55Z

AliHussein:

For the Basic Skills Project, Group 9 plans on focusing on Inequalities.

We will give several worked out examples to cover all cases of questions concerning this topic.

Also, we will include tips & tricks for how to solve more difficult problems and possible references related to the topic.

<pre>Let's work with Group 10 for the group project :D -- Ellen</pre>

=What is an inequality?=

A way to remember what Inequalities are is:

<pre>A statement indicating that the value of one quantity or expression is not equal to another, as in x ≠ y</pre>

''Collins Discovery Encyclopedia, 1st edition © HarperCollins Publishers 2005''

What that basically means is:

* When an equation is < or > or ≤ or ≥ than something.
** E.g. x + 1 ≤ 3

=Linear Inequalities=

The only difference between solving linear inequalities and solving linear equations is that '>' or '<' replaces the '=' sign.

Also, if you multiply or divide by a negative number, you have to change the sign around.

====Example 1====

Solve -2x > 2

we start by dividing both sides by -2 to solve the inequality

x < -1

====Example 2====
Solving linear inequalities is almost exactly like solving linear equations.

* Solve x + 3 < 0.

If they'd given "x + 3 = 0", we would know how to solve: we would have subtracted 3 from both sides. The same applies here.

x < -3

Then the solution is:

x < –3

====Example 3====

* Solve x – 4 > 0.

If they'd given "x – 4 = 0", then we would can solve by adding four to each side. The same applies here.
x >= 4

Then the solution is: x > 4

====Example 4====

* Solve 2x < 9.

If they had given "2x = 9", we would have divided the 2 from each side.

x <= 9/2

Then the solution is: x < 9/2

====Example 5====

* Solve (2x – 3)/4 < 2.
First, multiply through by 4. Since the "4" is positive, we don't have to flip the inequality sign:

(2x – 3)/4 < 2
(4) × (2x – 3)/4 < (4)(2)
2x – 3 < 8
2x < 11
x < 11/2 = 5.5
====Example 6====

* Solve 10 < 3x + 4 < 19.

This is what is called a "compound inequality". It works just like regular inequalities, except that it has three "sides". So, for instance, when we go to subtract the 4, I will have to subtract it from all three "sides".

=10 < 3x + 4 < 19
=6 < 3x < 15
=2 < x < 5
====Example 7====
* Solve 5x + 7 < 3(x + 1).

First we multiply through on the right-hand side, and then solve as usual:

5x + 7 < 3(x + 1)
5x + 7 < 3x + 3
2x + 7 < 3
2x < –4
x < –2

=Tips=
If x ≥ y then 1/x ≤ 1/y

=Quadratic Inequalities=
references:

http://www.purplemath.com/modules/ineqquad.htm

http://www.analyzemath.com/Inequalities_Polynomial/quadratic_inequalities.html

====Example 1====

Solve <math>x^2-2x-15>0</math>

Treat it like a normal quadratic equation and find the zeroes
* <math>x^2-2x-15=0</math>
<math>(x-5)(x+3)=0</math>
x-5=0 or x+3=0
x=5 or -3

The zeroes divide the number line into three regions

[[File:Crappy_number_line_thing_1.png]]

For region x>5, check for a number greater than 5 (eg.6).
*<math>(6)^2-2(6)-15>0</math>
9>0
All x-values greater than 5 will work.

For region x<-3, check for a number less than -3 (eg.-4).
*<math>(-4)^2-2(-4)-15>0</math>
9>0
All x-values less than -3 will work.

*Show answer using interval notation
<math>(-infinity,-3)U(5,infinity)</math>

====Example 2====

Solve <math>3x^2>-x+4</math>

Make one side equal to zero
*<math>3x^2+x-4>0</math>

Find the zeroes using the quadratic formula and factor

*(3x+4)(x-1)>0
3x+4=0 or x-1=0
x=<math>-(4/3)</math> or 1

For region x><math>-(4/3)</math>, check for a number less than <math>-(4/3)</math> (eg.-2).
*<math>3(-2)^2+(-2)-4>0</math>
6>0
All x-values less than <math>-4/3</math> will work.

For region x>1, check for a number greater than 1 (eg.4).
*<math>3(4)^2+(4)-4>0</math>
48>0
All x-values greater than 1 will work.

*Show values that produce an answer greater than 0 using interval notation
<math>(-infinity, -4/3)U(1,+infinity)</math>

'''Graphing Inequalities'''

Number Line
1. Simplify the inequality you are going to graph.
-2x2 + 5x < -6(x + 1)
-2x2 + 5x < -6x – 6

2. Move all terms to one side so the other is zero. It will be easiest if the highest power variable is positive.
0 < 2x2 -6x - 5x - 6
0 < 2x2 -11x – 6

3. Pretend that the inequality sign is an equal sign and find all values of the variable.
0 = 2x2 -11x - 6
0 = (2x + 1)(x - 6)
2x + 1 = 0, x - 6 = 0
2x = -1, x = 6
x = -1/2

4. Draw a number line including the variable solutions (in order).

5. Draw a circle on the points. If the inequality symbol means less than or more than (> or <), draw an empty circle over the variable solution(s). If it means less/more than and equal to (≤ or ≥) fill in that circle.

In this case our equation was greater than zero, so use open circles.

6. Take a number from each of the resulting intervals and plug it back into the equality. If you get a true statement once solved, shade this region of the number line.

In the interval from (-∞,-1/2) we will take -1 and plug it into the original inequality.
0 < 2x2 -11x - 6
0 < 2(-1)2 -11(-1) - 6
0 < 2(1) + 11 - 6
0 < 7
Zero is less than 7 is correct, so shade (-∞, -1/2) on the number line.

7. Next, on the interval from (-1/2, 6) we will use zero.
0 < 2(0)2 -11(0) - 6
0 < 0 + 0 - 6
0 < -6
Zero is not less than negative six, so do not shade (-1/2,6).

Lastly, we will take 10 from the interval (6,∞).
0 < 2(10)2 - 11(10) + 6
0 < 2(100) - 110 + 6
0 < 200 - 110 + 6
0 < 96
Zero is less than 96 is correct, so shade (6,∞) as well.

Use arrows on the end of shading to indicate that the interval continues into infinity. The completed number line:

=Videos teaching Inequality=

Video 1. http://www.khanacademy.org/video/inequalities?playlist=Algebra%20I%20Worked%20Examples
- This video touches upon the concept of inequality and has a basic word problem solved.

Video 2. http://www.khanacademy.org/video/interpreting-inequalities?playlist=Algebra%20I%20Worked%20Examples
- This video is about interpreting inequalities in word problems.

Video 3. http://www.khanacademy.org/video/solving-inequalities?playlist=Algebra%20I%20Worked%20Examples
- This video is about solving basic problems regarding inequalities.

Video 4. http://www.khanacademy.org/video/inequalities-using-addition-and-subtraction?playlist=ck12.org%20Algebra%201%20Examples
- This video solves random question about inequalities with addition and subtraction.

Video 5. http://www.khanacademy.org/video/inequalities-using-multiplication-and-division?playlist=ck12.org%20Algebra%201%20Examples
- This video solves random question about inequalities with multiplication and division

Video 6. http://www.khanacademy.org/video/quadratic-inequalities?playlist=Algebra
- This video explains quadratic Inequalities.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09/Homework 4

2010-10-20T05:52:33Z

AliHussein:

Q1: Ellen

Q2: Kazi

Q3: Maria

Q4: Ali

Q5: Edith

==Problem 1==
'''Five persons named their pets after each other. From the following clues, can you decide which pet belongs to Suzan's mother?
* Tosh owns a cat,
* Bianca owns a frog that she loves,
* Jaela owns a parrot which keeps calling her "darling, darling",
* Jun owns a snake, don't mess with him,
* Suzan is the name of the frog,
* The cat is named Jun,
* The name by which they call the turtle is the name of the woman whose pet is Tosh,
* Finally, Suzan's mother's pet is Bianca.'''

---

From this question we can derive several general things:
* There are 5 people with 5 pets, and the pets cannot be named after their owners.
* One of the following 4 people are Suzan's mother: Tosh, Jun, Jaela or Bianca. (It cannot be Suzan herself)
* Be careful not to assume that Tosh and Jun are male.

From the clues we can see that:

* Tosh owns a cat - Jun
* Bianca owns a frog - Suzan
* Jaela owns a parrot - Tosh or Bianca
* Jun owns a snake - Tosh or Bianca
* Suzan owns a turtle (by elimination, the rest is given in the clues) - Jaela or Jun (Name of the woman whose pet is Tosh)

Suzan owns a turtle which:
* cannot be named Bianca, because Bianca is the name of Suzan's mother's pet
* cannot be named Jun, because that is the cat's name
* cannot be named Tosh, because the name of the turtle is the name of the woman whose pet is Tosh, and a pet cannot be named after its owner.

Hence, by elimination, the turtle is called Jaela.

"The name by which they call the turtle is the name of the woman whose pet is Tosh".
The turtle is called Jaela, therefore Jaela (the person) must own Tosh.
Jaela owns a parrot, therefore the parrot must be Tosh.

The only pet name left is Bianca. Therefore, by elimination, the name of the snake is Bianca.

"Suzan's mother's pet is Bianca". Hence, Suzan's mother must be Jun.

[[File:Hw4q1pets.jpg]]

Yay, picture!

==Problem 2==
'''Bohao, Stewart, Dylan, Tim and Chan are the five players of a basketball team. Two are left handed and three right handed, Two are over 2m tall and three are under 2m, Bohao and Dylan are of the same handedness, whereas Tim and Chan use different hands. Stewart and Chan are of the same height range, while Dylan and Tim are in different height ranges. If you know that the one playing centre is over 2m tall and is left handed, can you guess his name?'''

==Problem 3==
'''Adam, Bobo, Charles, Ed, Hassan, Jason, Mathieu, Pascal and Sung have formed a baseball team. The following facts are true:
* Adam does not like the catcher,
* Ed's sister is engaged to the second baseman,
* The centre fielder is taller than the right fielder,
* Hassan and the third baseman live in the same building,
* Pascal and Charles each won $20 from the pitcher at a poker game,
* Ed and the outfielders play cards during their free time,
* The pitcher's wife is the third baseman's sister,
* All the battery and infield except Charles, Hassan and Adam are shorter than Sung,
* Pascal, Adam and the shortstop lost $100 each at the race track,
* The second baseman beat Pascal, Hassan, Bobo and the catcher at billiards,
* Sung is in the process of getting a divorce,
* The catcher and the third baseman each have two legitimate children,
* Ed, Pascal Jason, the right fielder and the centre fielder are bachelors, the others are all married
* The shortstop, the third baseman and Bobo all attended the fight,
* Mathieu is the shortest player of the team,
Determine the positions of each player on the baseball team.'''

''Note: On a baseball team there are three outfielders (right, centre and left), four infielders (first baseman, second baseman, third baseman and shortstop) and the battery (pitcher and catcher).''

'''Adam'''
*cannot be:

the catcher unless he dislikes himself

an outfielder because it says he's either part of the battery or infield

shortstop

right or centre fielder because he's married

2nd baseman because he's already married and can't be engaged to Ed's sister

'''Ed'''
*cannot be the second baseman unless he is in an incestuous relationship and is engaged to his own sister

'''Mathieu'''
*cannot be the centre fielder because he is the shortest

''*only person that can be right fielder according to information given
''

'''Hassan'''
*cannot be an outfielder because it says he's either part of the battery or infield

third baseman

second baseman

catcher

right or centre fielder because he's married

'''Ed'''
*cannot be:

right

left

centre

(outfielder)

*because he's still a bachelor cannot have two legitimate children-->cannot be catcher or third baseman

'''Charles'''
*cannot be:

an outfielder because it says he's either part of the battery or infield

since he cannot be right or centre fielder, it means that he's married

2nd baseman because he's already married and can't be engaged to Ed's sister

pitcher since he won $20 from him at a poker game

'''Pascal'''
*cannot be:

shortstop

second baseman

catcher

right fielder

centre fielder

pitcher since he won $20 from him at a poker game

*because he's still a bachelor cannot have two legitimate children-->cannot be catcher or third baseman

'''Bobo'''
*cannot be:

second baseman

catcher

third baseman

shortstop

right fielder because he is the only person who can be centre fielder

''*only person that can be centre fielder according to information given
''

'''Sung'''
*is still married and, therefore, cannot be engaged to Ed's sister (yet)-->cannot be 2nd baseman
*cannot be right or centre fielder because he's married

'''Jason'''
*cannot be:

right fielder

centre fielder

*because he's still a bachelor cannot have two legitimate children-->cannot be catcher or third baseman
[[File:14csb4g.png‎ ]]

Using the information given, it can be concluded that only

Pascal and Sung can be the left fielder

Adam, Charles, Ed, Hassan, Pascal, and Sung can be the 1st baseman

Adam, Charles, and Sung can be the 3rd baseman

Charles, Ed, Hassan, and Sung can be the shortstop

Adam, Hassan, and Sung can be the pitcher

Charles and Sung can be the catcher

''Sung can be any of the remaining positions'', but Ed can only be the 1st baseman or the shortstop. Pascal can only be the left fielder or the 1st baseman. Charles is the only other person that can be the catcher.

If Sung is the shortstop, that means that Ed would have to be the 1st baseman, Pascal would have to be the left fielder, and Charles would have to be the catcher.
This leaves Hassan as the only person that can be the pitcher and Adam as the 3rd baseman.

* Adam is the third baseman
* Bobo is the centre fielder
* Charles is the catcher
* Ed is the first baseman
* Hassan is the pitcher
* Jason is the second baseman
* Mathieu is the right fielder
* Pascal is the left fielder
* Sung is the shortstop

==Problem 4==
'''Six players - Petra, Carla, Janet, Sandra, Li and Fernanda - are competing in a chess tournament over a period of five days. Each player plays each of the others once. Three matches are played simultaneously during each of the five days. The first day, Carla beats Petra after 36 moves. The second day, Carla was again victorious when Janet failed to complete 40 moves within the required time limit. The third day had the most exciting match of all when Janet declared that she would checkmate Li in 8 moves and succeeded in doing so. On the fourth day, Petra defeated Sandra. Who played against Fernanda on the fifth day?'''

*==Problem 4==
'''Six players - Petra, Carla, Janet, Sandra, Li and Fernanda - are competing in a chess tournament over a period of five days. Each player plays each of the others once. Three matches are played simultaneously during each of the five days. The first day, Carla beats Petra after 36 moves. The second day, Carla was again victorious when Janet failed to complete 40 moves within the required time limit. The third day had the most exciting match of all when Janet declared that she would checkmate Li in 8 moves and succeeded in doing so. On the fourth day, Petra defeated Sandra. Who played against Fernanda on the fifth day?'''

* Carla played against fernando on the fifth day. this is clearly shown by the following list:

1st day 2nd day 3rd day 4th day 5th day

Carla Vs Petra Carla vs Janet Janet vs Li Petra vs Sandra Fernando vs Carla
Janet vs sandra Petra vs Li Carla vs sandra Li vs carla Janet vs Petra
Li vs Fernando Sandra vs fernando Petra vs Fernando Fernando vs Janet Li vs Sandra

Taking into account the matches given, assume the other matches were also played. then this gives the information above. Therefore the answer is Carla.

==Problem 5==
'''Homer finally had a week off from his job at the nuclear power plant and intended to spend all nine days of his vacation (Saturday through the following Sunday) sleeping late. But his plans were foiled by some of the people who work in his neighbourhood.'''

*On Saturday, his first morning off, Homer was wakened by the doorbell; it was a salesman of magazine subscriptions.
*On Sunday, the barking of the neighbour's dog abruptly ended Homer's sleep.
*On Monday, he was again wakened by the persistent salesman but was able to fall asleep again, only to be disturbed by the construction workers next door.
*In fact, the salesman, the neighbour's dog and the construction workers combined to wake Homer at least once each day of his vacation, with only one exception.
*The salesman woke him again on Wednesday; the construction workers on the second Saturday; the dog on Wednesday and on the final Sunday.
*No one of the three noisemakers was quiet for three consecutive days; but yet, no pair of them made noise on more than one day during Homer's vacation. On which day of his holiday was Homer actually able to sleep late?

S = Salesman

D = Neighbour's dog

C = Construction Workers

Confirmed:

Sat: S

Sun: D

Mon: S+C

Tues: ?

Wed: S+D

Thurs: ?

Fri: ?

Sat: C

Sun: D

Important!

== //No one of the three noisemakers was quiet for three consecutive days

== //No pair of them made noise on more than one day during Homer's vacation

--> Then it means that there could be a pair of construction workers + dog on a certain day

// The construction worker has to bother Homer on Thursday .

// From above information, the salesman has to come by on Friday (as the last confirmed date he came by is Wednesday) as he can't come by on Thursday.

// The last time the dog barks is on Sunday so the dog has to bark on a day not past Thursday. But the above information states on pair makes noise for more than a day so the dog has to bark on Thursday. It will work as the construction workers and dog didn't combine their forces for any time in the confirmed information.

Chart:

Sat: S

Sun: D

Mon: S+C

Tues: ? ==> REST!!

Wed: S+D

Thurs: ? ==> C+D

Fri: ? ==> S

Sat: C

Sun: D

Then with all the combined information, the holiday day where Homer gets to sleep in has to be Tuesday.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-13T07:23:48Z

AliHussein:

Group members:
* Kazi Ahmed
* Edith Fan | xsaret@gmail.com
* Maria Fayloga | maria.fayloga@gmail.com
* Ali Hussein
* Ellen Tsang | ellentsang.nl@hotmail.com

=Homework 3, third part - Problem-Solving Skills=

==Q1==
'''A bus traveled from the terminal to the airport at an average speed of 30 mi/hr and the trip took an hour and 20 min. The bus then traveled from the airport back to the terminal and again averaged 30 mi/hr. However, the return trip required 80 min. Explain.'''

The average speed for both the journey from the terminal to the airport and the journey from the airport back to the terminal is 30 mi/hr.
So why does one take 1 hour 20 min and the other take 80 min?

The time taken for the bus to travel from the terminal to the airport is:
1 hour = 60 min
1 hour 20 min = 60 + 20 = 80 min

This is the same as the time taken for the bus to travel from the airport back to the terminal, 80 min.

Hence, it can be concluded that the time taken to and back from the airport is the same, 80 min.

==Q2==
'''A lady did not have her driver's license with her when she failed to stop at a stop sign and then went three blocks down a one-way street the wrong way. A policeman saw her, but he did not stop her. Explain.'''

From this question we can note 3 things:
* The lady did not have her driver's license
* She failed to stop at a stop sign
* She went 3 blocks down a one-way street the wrong way
However, the policeman noted all this but did not stop her.

All of the above is assumed to be violations if the lady were driving, and the policeman should have stopped her.

However, the question never stated that she was driving.

Hence, the logical conclusion is that the lady was probably walking, running or some other similar method of travelling.

==Q3==
'''One of three boxes contains apples, another box contains oranges, and another box contains a mixture of apples and oranges. The boxes are labeled APPLES, ORANGES and APPLES AND ORANGES, but each label is incorrect. Can you select one fruit from only one box and determine the correct labels? Explain.'''

For example:

BOX 1: APPLES

BOX 2: ORANGES

BOX 3: APPLES & ORANGES

We know all the boxes have incorrect labels, therefore the labels for the boxes are:

BOX 1: ORANGES or APPLES & ORANGES

BOX 2: APPLES or APPLES & ORANGES

BOX 3: APPLES or ORANGES

==Q11==
'''A woman, her older brother, her son, and her daughter are chess players. The worst player’s twin, who is one of the four players, and the best player are of opposite sex. The worst player and the best player have the same age. If this is possible, who is the worst player?'''

Either the son or the daughter-this is because the mother and brother cant be twins since the brother is older.

==Q12==
'''A Manhattan fellow had a girlfriend in the Bronx and a girlfriend in Brooklyn. He decided which girlfriend to visit by arriving randomly at the train station and taking the first of the Bronx or Brooklyn trains that arrived. The trains to Brooklyn and the Bronx each arrived regularly every 10 minutes. Not long after he began his scheme the man's Bronx girlfriend left him because he rarely visited. Give a (logical) explanation.'''

This happened because the trains to Brooklyn are minutes ahead of trains to Bronx and they arrive earlier though they take the same time; 10 minutes. since he takes the train that arrives first, he ends up rarely visiting his girl friend in Bronx, hence they broke up.

==Q13==
'''If a clock takes 5 seconds to strike 5:00 (with 5 equally spaced chimes), how long does it take to strike 10:00 (with 10 equally spaced chimes)?'''

10 seconds. this is because the ratio 5 seconds to 5 spaced chimes is equal to 1. 5:5=1 then ten strikes with ten spaced chimes takes ten seconds

==Q14==
'''One day in the maternity ward, the name tags for four girl babies became mixed up. (i) In how many different ways could two of the babies be tagged correctly and two of the babies be tagged incorrectly? (ii) In how many different ways could three of the babies be tagged correctly and one baby be tagged incorrectly?'''

(i) There are six different ways of tagging two of the babies correctly and two incorrectly.

(ii) It is impossible to get three of the babies tagged correctly and one incorrectly since there are only four in number and if three are tagged correctly, then the remaining will obviously be tagged correctly also.

==Q15==
'''Alex says to you, “I'll bet you any amount of money that if I shuffle this deck of cards, there will always be as many red cards in the first half of the deck as there are black cards in the second half of the deck.” Should you accept his bet?'''

ANS: I would neither accept nor refuse, since there are 52 cards in a deck and consists of 26 red cards and 26 black cards. this is because the probability of getting red or blacks cards in the first half and second half is the same, 1/2.

==Q16==

Let:
D= number of daughters
S= number of sons

The daughter with the same number of brother and sisters also counts as another sister. Therefore, there is one less son than there are daughters:
S=D-1

"Each son has twice as many sisters as he has brothers" can be represented as:
D=2(S-1)

==Q17==

I don't really know what's goin on here...but 105 kg-60 kg= 45 kg and 105 kg- 50 kg =55 kg and both those numbers give a reading that's 5 kg smaller than the number given when just one person steps on the scale.

So the scale gives readings that are higher?

==Q18==

If 1/3 is taken out each time, that means 2/3 is left in the jar each time. If you multiply the remaining 40 by 2/3's reciprocal, you should get the previous amount, since 2/3*3/2=1.

==Q19==
I don't get this one...

==Q20==

The clocks initially are 10 minutes apart.
60 min/h
60 min/10 min

==Q21==

Sven = middle of all runners so the total amount of runners should be odd -> middle of 7 is 4; but there is no middle of say, 8.

Dan is slower than Sven (in tenth place) so -> Sven > 10

Lars is in 16th place so Sven > Dan > 16

- assumed that Lars is not last as it was not stated explicitly in the question then the total runners > 16.

Therefore, the total number of runners has to be 17 because if the total number of runners exceed that, say, 19 then Sven would be number 20. However, that is not possible as the question states that he is slower than Sven at 10th place; Sven and Dan can not coexist in the same place number.

==Q22==

If we designate raining as R and sunny periods of time as S then we can make a simple table.

First, if it rains in the morning ---> afternoon is sunny

- rainy afternoon ---> sunny morning

Total R = 13

11 Sunny mornings

12 Sunny afternoons

Morn - R S S S S R R S S S S S R R S S R R

Noon - S S R R S S S R R S R S S S R S S S

^Sunny Mornings = 11

Sunny Noon = 12

Rainy = 13

--> Total days of vacation = 18

==Q23==

Products of age = 36

Oldest child = x

Second child = y

Third child = z

- then x * y * z = 36

Sum of all ages = a date

- then x + y + z = d ;; but d <= 31 (the largest amount of days in a month is 31)

A way to go about this question is to list every possibility that x, y and z will multiply to 36.

[[File:Tttable.png]]

The original question states that Paul didn't get it even though it the ages add up to a date. The table above shows that all of the sums (or dates) are unique so the only possibilities are ages 2, 2, 9 and ages 1, 6, 6. However, if we assume that the oldest child and the second are not the same age (or twins) then we can say that x > y => z. So it leaves that Paula's children are ages 2, 2 and 9 respectively.

==Q24==

Time taken for candle A to burn out = 6 hours

Time taken for candle B to burn out = 3 hours

And to solve the question, we can say that Candle A = 2*Candle B

If we assume time starts at 0 and 'burning of the candle' is constant then:

Candle A = 6 hours then it means it will burn 1/6 per hour

Candle B = same as above; it will burn 1/3 per hour

Then Candle A = (6-x)/6

Candle B = (3-x)/6

x = time in hours

- as stated above: Candle A = 2(Candle B)

Then if we calculate the two states of Candle B before it burns out and not at its full length:

<math>2((x-3)/3) = (6-x)/6</math>

<math>6(6-2x) = 3(6-x)</math>

<math>36-12x = 18-3x</math>

<math>18 = 9x</math>

<math>x = 2 hours</math>

So the time it takes for one of the candle to be half of the other candle is 2 hours.

==Q25==

Candle A has length L and is lit at 6 h.

Candle B has length (L + 1) and is lit at 4.5 h.

At 8.5 h, Candle A = Candle B

Candle A burns out at 10 h while Candle B burns out at 10.5 h. Then the total burning time of Candle A = 10-6 = 4h; Candle B = 10.5-4.5 = 6h.

Burning time till 8.5h for Candle A = 8.5 - 6 = 2.5h

Burning time till 8.5h for Candle B = 8.5 - 4.5 = 4h

let x = candle a length ;; aka. L

let y = candle b length

--> y = x+1

let b1 = burning constant for x

let b2 = burning constant for y

-> Candle A = Candle B at 8.5 h

<math>x-4*B1 = x+1-2.5B2</math>

--> x cancels out to

<math>4*B1 = 1-2.5B2</math>

---> What at B1 and B2 then?

<math>y=6B2</math> ;; at end time

<math>x=4B1</math> ;; at end time

<math> x = y</math>

<math>6B2 = 4B1 + 1</math> ;; the one comes from x+1

<math>B2 = (4B1+1)/6</math>

<math>B1 = (6B1-1)/4</math>
Using the above equations and substituting back into the original

---> <math>4*B2 = 1-2.5B1</math>

<math>4*B2 = 1-2.5((6B2-1)/4)</math>

<math>4*B2 = 1-((15B2-2.5)/4)</math>

<math>4(4B2-1) = 15B2-2.5</math>

<math>16B2-4 = 15B2-2.5</math>

<math>B2 = -2.5+4</math>

<math>B2=1.5</math> <-- plug in back to y=6B2

<math>4*((4B1+1)/6) = 1-2.5B1</math>

<math>B1=2</math> <-- plug in back to x = 4B1

<math> y = 6B2</math>

<math> y = 6(1.5) = 9</math>

<math> x = 4B1</math>

<math> x = 4(2) = 8</math>

Length of Candle B (longer candle) is 9 units and the length of the Candle A (shorter candle) is 8 units.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-13T06:54:02Z

AliHussein:

Group members:
* Kazi Ahmed
* Edith Fan | xsaret@gmail.com
* Maria Fayloga | maria.fayloga@gmail.com
* Ali Hussein
* Ellen Tsang | ellentsang.nl@hotmail.com

=Homework 3, third part - Problem-Solving Skills=

==Q1==
'''A bus traveled from the terminal to the airport at an average speed of 30 mi/hr and the trip took an hour and 20 min. The bus then traveled from the airport back to the terminal and again averaged 30 mi/hr. However, the return trip required 80 min. Explain.'''

The average speed for both the journey from the terminal to the airport and the journey from the airport back to the terminal is 30 mi/hr.
So why does one take 1 hour 20 min and the other take 80 min?

The time taken for the bus to travel from the terminal to the airport is:
1 hour = 60 min
1 hour 20 min = 60 + 20 = 80 min

This is the same as the time taken for the bus to travel from the airport back to the terminal, 80 min.

Hence, it can be concluded that the time taken to and back from the airport is the same, 80 min.

11. A woman, her older brother, her son, and her daughter are chess players. The worst player’s twin, who is one of the four players, and the best player are of opposite sex. The worst player and the best player have the same age. If this is possible, who is the worst player?

ANS: either the son or the daughter

12. A Manhattan fellow had a girlfriend in the Bronx and a girlfriend in Brooklyn. He decided which girlfriend to visit by arriving randomly at the train station and taking the first of the Bronx or Brooklyn trains that arrived. The trains to Brooklyn and the Bronx each arrived regularly every 10 minutes. Not long after he began his scheme the man's Bronx girlfriend left him because he rarely visited. Give a (logical) explanation.

ANS: this happened because the trains to Brooklyn are minutes ahead of trains to Bronx and they arrive earlier though they take the same time; 10 minutes. since he takes the train that arrives first, he ends up visitting rarely his girl freind in Bronx, hence the broke up.

13. If a clock takes 5 seconds to strike 5:00 (with 5 equally spaced chimes), how long does it take to strike 10:00 (with 10 equally spaced chimes)?
ANS: 10 seconds

==Q14==
'''One day in the maternity ward, the name tags for four girl babies became mixed up. (i) In how many different ways could two of the babies be tagged correctly and two of the babies be tagged incorrectly? (ii) In how many different ways could three of the babies be tagged correctly and one baby be tagged incorrectly?'''
ANS:
(i) There are six different ways of tagging two of the babies correctly and two incorrectly.

(ii) It is impossible to get three of the babies tagged correctly and one incorrectly since there are only four in number and if three are tagged correctly, then the remaining will obviously be tagged correctly also.

==Q15==
'''Alex says to you, “I'll bet you any amount of money that if I shuffle this deck of cards, there will always be as many red cards in the first half of the deck as there are black cards in the second half of the deck.” Should you accept his bet?'''

ANS: I would neither accept nor refuse, since there are 52 cards in a deck and consists of 26 red cards and 26 black cards. this is because the probability of getting red or blacks cards in the first half and second half is the same, 1/2.

==Q21==

Sven = middle of all runners so the total amount of runners should be odd -> middle of 7 is 4; but there is no middle of say, 8.

Dan is slower than Sven (in tenth place) so -> Sven > 10

Lars is in 16th place so Sven > Dan > 16

- assumed that Lars is not last as it was not stated explicitly in the question then the total runners > 16.

Therefore, the total number of runners has to be 17 because if the total number of runners exceed that, say, 19 then Sven would be number 20. However, that is not possible as the question states that he is slower than Sven at 10th place; Sven and Dan can not coexist in the same place number.

==Q22==

If we designate raining as R and sunny periods of time as S then we can make a simple table.

First, if it rains in the morning ---> afternoon is sunny

- rainy afternoon ---> sunny morning

Total R = 13

11 Sunny mornings

12 Sunny afternoons

Morn - R S S S S R R S S S S S R R S S R R

Noon - S S R R S S S R R S R S S S R S S S

^Sunny Mornings = 11

Sunny Noon = 12

Rainy = 13

--> Total days of vacation = 18

==Q23==

Products of age = 36

Oldest child = x

Second child = y

Third child = z

- then x * y * z = 36

Sum of all ages = a date

- then x + y + z = d ;; but d <= 31 (the largest amount of days in a month is 31)

A way to go about this question is to list every possibility that x, y and z will multiply to 36.

[[File:Tttable.png]]

The original question states that Paul didn't get it even though it the ages add up to a date. The table above shows that all of the sums (or dates) are unique so the only possibilities are ages 2, 2, 9 and ages 1, 6, 6. However, if we assume that the oldest child and the second are not the same age (or twins) then we can say that x > y => z. So it leaves that Paula's children are ages 2, 2 and 9 respectively.

==Q24==

Time taken for candle A to burn out = 6 hours

Time taken for candle B to burn out = 3 hours

And to solve the question, we can say that Candle A = 2*Candle B

If we assume time starts at 0 and 'burning of the candle' is constant then:

Candle A = 6 hours then it means it will burn 1/6 per hour

Candle B = same as above; it will burn 1/3 per hour

Then Candle A = (6-x)/6

Candle B = (3-x)/6

x = time in hours

- as stated above: Candle A = 2(Candle B)

Then if we calculate the two states of Candle B before it burns out and not at its full length:

<math>2((x-3)/3) = (6-x)/6</math>

<math>6(6-2x) = 3(6-x)</math>

<math>36-12x = 18-3x</math>

<math>18 = 9x</math>

<math>x = 2 hours</math>

So the time it takes for one of the candle to be half of the other candle is 2 hours.

==Q25==

Candle A has length L and is lit at 6 h.

Candle B has length (L + 1) and is lit at 4.5 h.

At 8.5 h, Candle A = Candle B

Candle A burns out at 10 h while Candle B burns out at 10.5 h. Then the total burning time of Candle A = 10-6 = 4h; Candle B = 10.5-4.5 = 6h.

Burning time till 8.5h for Candle A = 8.5 - 6 = 2.5h

Burning time till 8.5h for Candle B = 8.5 - 4.5 = 4h

let x = candle a length ;; aka. L

let y = candle b length

--> y = x+1

let b1 = burning constant for x

let b2 = burning constant for y

-> Candle A = Candle B at 8.5 h

<math>x-4*B1 = x+1-2.5B2</math>

--> x cancels out to

<math>4*B1 = 1-2.5B2</math>

---> What at B1 and B2 then?

<math>y=6B2</math> ;; at end time

<math>x=4B1</math> ;; at end time

<math> x = y</math>

<math>6B2 = 4B1 + 1</math> ;; the one comes from x+1

<math>B2 = (4B1+1)/6</math>

<math>B1 = (6B1-1)/4</math>
Using the above equations and substituting back into the original

---> <math>4*B2 = 1-2.5B1</math>

<math>4*B2 = 1-2.5((6B2-1)/4)</math>

<math>4*B2 = 1-((15B2-2.5)/4)</math>

<math>4(4B2-1) = 15B2-2.5</math>

<math>16B2-4 = 15B2-2.5</math>

<math>B2 = -2.5+4</math>

<math>B2=1.5</math> <-- plug in back to y=6B2

<math>4*((4B1+1)/6) = 1-2.5B1</math>

<math>B1=2</math> <-- plug in back to x = 4B1

<math> y = 6B2</math>

<math> y = 6(1.5) = 9</math>

<math> x = 4B1</math>

<math> x = 4(2) = 8</math>

Length of Candle B (longer candle) is 9 units and the length of the Candle A (shorter candle) is 8 units.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-13T06:52:19Z

AliHussein:

Group members:
* Kazi Ahmed
* Edith Fan | xsaret@gmail.com
* Maria Fayloga | maria.fayloga@gmail.com
* Ali Hussein
* Ellen Tsang | ellentsang.nl@hotmail.com

=Homework 3, third part - Problem-Solving Skills=

==Q1==
'''A bus traveled from the terminal to the airport at an average speed of 30 mi/hr and the trip took an hour and 20 min. The bus then traveled from the airport back to the terminal and again averaged 30 mi/hr. However, the return trip required 80 min. Explain.'''

The average speed for both the journey from the terminal to the airport and the journey from the airport back to the terminal is 30 mi/hr.
So why does one take 1 hour 20 min and the other take 80 min?

The time taken for the bus to travel from the terminal to the airport is:
1 hour = 60 min
1 hour 20 min = 60 + 20 = 80 min

This is the same as the time taken for the bus to travel from the airport back to the terminal, 80 min.

Hence, it can be concluded that the time taken to and back from the airport is the same, 80 min.

11. A woman, her older brother, her son, and her daughter are chess players. The worst player’s twin, who is one of the four players, and the best player are of opposite sex. The worst player and the best player have the same age. If this is possible, who is the worst player?

ANS: either the son or the daughter

12. A Manhattan fellow had a girlfriend in the Bronx and a girlfriend in Brooklyn. He decided which girlfriend to visit by arriving randomly at the train station and taking the first of the Bronx or Brooklyn trains that arrived. The trains to Brooklyn and the Bronx each arrived regularly every 10 minutes. Not long after he began his scheme the man's Bronx girlfriend left him because he rarely visited. Give a (logical) explanation.

ANS: this happened because the trains to Brooklyn are minutes ahead of trains to Bronx and they arrive earlier though they take the same time; 10 minutes. since he takes the train that arrives first, he ends up visitting rarely his girl freind in Bronx, hence the broke up.

13. If a clock takes 5 seconds to strike 5:00 (with 5 equally spaced chimes), how long does it take to strike 10:00 (with 10 equally spaced chimes)?
ANS: 10 seconds

==Q14==
'''One day in the maternity ward, the name tags for four girl babies became mixed up. (i) In how many different ways could two of the babies be tagged correctly and two of the babies be tagged incorrectly? (ii) In how many different ways could three of the babies be tagged correctly and one baby be tagged incorrectly?'''
ANS:
(i) There are six different ways of tagging two of the babies correctly and two incorrectly.

(ii) It is impossible to get three of the babies tagged correctly and one incorrectly since there are only four in number and if three are tagged correctly, then the remaining will obviously be tagged correctly also.

==Q15==
'''Alex says to you, “I'll bet you any amount of money that if I shuffle this deck of cards, there will always be as many red cards in the first half of the deck as there are black cards in the second half of the deck.” Should you accept his bet?'''

ANS: I would neither accept nor refuse since there are 52 cards in a deck and consists of 26 red cards and 26 black cards. this is because the probility of getting red or blacks cards in the first half and second half is the same, 1/2.

==Q21==

Sven = middle of all runners so the total amount of runners should be odd -> middle of 7 is 4; but there is no middle of say, 8.

Dan is slower than Sven (in tenth place) so -> Sven > 10

Lars is in 16th place so Sven > Dan > 16

- assumed that Lars is not last as it was not stated explicitly in the question then the total runners > 16.

Therefore, the total number of runners has to be 17 because if the total number of runners exceed that, say, 19 then Sven would be number 20. However, that is not possible as the question states that he is slower than Sven at 10th place; Sven and Dan can not coexist in the same place number.

==Q22==

If we designate raining as R and sunny periods of time as S then we can make a simple table.

First, if it rains in the morning ---> afternoon is sunny

- rainy afternoon ---> sunny morning

Total R = 13

11 Sunny mornings

12 Sunny afternoons

Morn - R S S S S R R S S S S S R R S S R R

Noon - S S R R S S S R R S R S S S R S S S

^Sunny Mornings = 11

Sunny Noon = 12

Rainy = 13

--> Total days of vacation = 18

==Q23==

Products of age = 36

Oldest child = x

Second child = y

Third child = z

- then x * y * z = 36

Sum of all ages = a date

- then x + y + z = d ;; but d <= 31 (the largest amount of days in a month is 31)

A way to go about this question is to list every possibility that x, y and z will multiply to 36.

[[File:Tttable.png]]

The original question states that Paul didn't get it even though it the ages add up to a date. The table above shows that all of the sums (or dates) are unique so the only possibilities are ages 2, 2, 9 and ages 1, 6, 6. However, if we assume that the oldest child and the second are not the same age (or twins) then we can say that x > y => z. So it leaves that Paula's children are ages 2, 2 and 9 respectively.

==Q24==

Time taken for candle A to burn out = 6 hours

Time taken for candle B to burn out = 3 hours

And to solve the question, we can say that Candle A = 2*Candle B

If we assume time starts at 0 and 'burning of the candle' is constant then:

Candle A = 6 hours then it means it will burn 1/6 per hour

Candle B = same as above; it will burn 1/3 per hour

Then Candle A = (6-x)/6

Candle B = (3-x)/6

x = time in hours

- as stated above: Candle A = 2(Candle B)

Then if we calculate the two states of Candle B before it burns out and not at its full length:

<math>2((x-3)/3) = (6-x)/6</math>

<math>6(6-2x) = 3(6-x)</math>

<math>36-12x = 18-3x</math>

<math>18 = 9x</math>

<math>x = 2 hours</math>

So the time it takes for one of the candle to be half of the other candle is 2 hours.

==Q25==

Candle A has length L and is lit at 6 h.

Candle B has length (L + 1) and is lit at 4.5 h.

At 8.5 h, Candle A = Candle B

Candle A burns out at 10 h while Candle B burns out at 10.5 h. Then the total burning time of Candle A = 10-6 = 4h; Candle B = 10.5-4.5 = 6h.

Burning time till 8.5h for Candle A = 8.5 - 6 = 2.5h

Burning time till 8.5h for Candle B = 8.5 - 4.5 = 4h

let x = candle a length ;; aka. L

let y = candle b length

--> y = x+1

let b1 = burning constant for x

let b2 = burning constant for y

-> Candle A = Candle B at 8.5 h

<math>x-4*B1 = x+1-2.5B2</math>

--> x cancels out to

<math>4*B1 = 1-2.5B2</math>

---> What at B1 and B2 then?

<math>y=6B2</math> ;; at end time

<math>x=4B1</math> ;; at end time

<math> x = y</math>

<math>6B2 = 4B1 + 1</math> ;; the one comes from x+1

<math>B2 = (4B1+1)/6</math>

<math>B1 = (6B1-1)/4</math>
Using the above equations and substituting back into the original

---> <math>4*B2 = 1-2.5B1</math>

<math>4*B2 = 1-2.5((6B2-1)/4)</math>

<math>4*B2 = 1-((15B2-2.5)/4)</math>

<math>4(4B2-1) = 15B2-2.5</math>

<math>16B2-4 = 15B2-2.5</math>

<math>B2 = -2.5+4</math>

<math>B2=1.5</math> <-- plug in back to y=6B2

<math>4*((4B1+1)/6) = 1-2.5B1</math>

<math>B1=2</math> <-- plug in back to x = 4B1

<math> y = 6B2</math>

<math> y = 6(1.5) = 9</math>

<math> x = 4B1</math>

<math> x = 4(2) = 8</math>

Length of Candle B (longer candle) is 9 units and the length of the Candle A (shorter candle) is 8 units.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-13T05:33:04Z

AliHussein:

Group members:
* Kazi Ahmed
* Edith Fan | xsaret@gmail.com
* Maria Fayloga | maria.fayloga@gmail.com
* Ali Hussein
* Ellen Tsang | ellentsang.nl@hotmail.com

14. One day in the maternity ward, the name tags for four girl babies became mixed up. (i) In how many different ways could two of the babies be tagged correctly and two of the babies be tagged incorrectly? (ii) In how many different ways could three of the babies be tagged correctly and one baby be tagged incorrectly?

ANS: (I)there are six different ways of tagging two of the babies correctly and two incorrectly. (II) it is impossible to get three of the babies tagged correctly and one incorrectly since there are only four in number and if three are tagged correctly, then the remaining will obviously be tagged correctly also.

15. Alex says to you, “I'll bet you any amount of money that if I shuffle this deck of cards, there will always be as many red cards in the first half of the deck as there are black cards in the second half of the deck.” Should you accept his bet?

ANS: i would neither accept nor refuse since there are 52 cards in a deck and consists of 26 red cards and 26 black cards. this is because the probility of getting red or blacks cards in the first half and second half is the same; 1/2

Course talk:MATH110/003/Groups/Group 09

2010-10-13T03:16:37Z

AliHussein:

=Homework 3, third part - Problem-Solving Skills=

==Q1==
'''1. A bus traveled from the terminal to the airport at an average speed of 30 mi/hr and the trip took an hour and 20 min. The bus then traveled from the airport back to the terminal and again averaged 30 mi/hr. However, the return trip required 80 min. Explain.'''

Isn't it just that the bus travelled a different (shorter) route? Haha.

i think for this question the time taken the bus is just the same! for because an hour and 20 min is quall to 80 min
==Q21==

Sven placed exactly in the middle among all runners in a race. Dan was slower than Sven, in 10th place, and Lars was in 16th place. How many runners were in the race?

Sven = x/2

y = total number of runners

Dan is slower than Sven so -> Sven > Dan

Lars is in 16th place so Sven > Dan > Lars

==Q22==

If we designate raining as R and sunny periods of time as S then we can make a simple table.

First, if it rains in the morning ---> afternoon is sunny

- rainy afternoon ---> sunny morning

Total R = 13

11 Sunny mornings

12 Sunny afternoons

Morn - R S S S S R R S S S S S R R S S R R

Noon - S S R R S S S R R S R S S S R S S S

^Sunny Mornings = 11

Sunny Noon = 12

Rainy = 13

--> Total days of vacation = 18

==Q23==

Products of age = 36

Oldest child = x

Second child = y

Third child = z

- then x * y * z = 36

Sum of all ages = a date

- then x + y + z = d ;; but d <= 31 (the largest amount of days in a month is 31)

A way to go about this question is to list every possibility that x, y and z will multiply to 36.

[[File:Tttable.png]]

The original question states that Paul didn't get it even though it the ages add up to a date. The table above shows that all of the sums (or dates) are unique so the only possibilities are ages 2, 2, 9 and ages 1, 6, 6. However, if we assume that the oldest child and the second are not the same age (or twins) then we can say that x > y => z. So it leaves that Paula's children are ages 2, 2 and 9 respectively.

==Q24==

Time taken for candle A to burn out = 6 hours

Time taken for candle B to burn out = 3 hours

And to solve the question, we can say that Candle A = 2*Candle B

If we assume time starts at 0 and 'burning of the candle' is constant then:

Candle A = 6 hours then it means it will burn 1/6 per hour

Candle B = same as above; it will burn 1/3 per hour

Then Candle A = (6-x)/6

Candle B = (3-x)/6

x = time in hours

- as stated above: Candle A = 2(Candle B)

Then if we calculate the two states of Candle B before it burns out and not at its full length:

<math>2((x-3)/3) = (6-x)/6</math>

<math>6(6-2x) = 3(6-x)</math>

<math>36-12x = 18-3x</math>

<math>18 = 9x</math>

<math>x = 2 hours</math>

So the time it takes for one of the candle to be half of the other candle is 2 hours.

==Q25==

Candle A has length L and is lit at 6 h.

Candle B has length (L + 1) and is lit at 4.5 h.

At 8.5 h, Candle A = Candle B

Candle A burns out at 10 h while Candle B burns out at 10.5 h. Then the total burning time of Candle A = 10-6 = 4h; Candle B = 10.5-4.5 = 2h.

Burning time till 8.5h for Candle A = 8.5 - 6 = 2.5h

Burning time till 8.5h for Candle B = 8.5 - 4.5 = 4h

-> Candle A = Candle B

<math>L-2.5a = (L+1)-4b </math>

--> Then what is a and b which are the values of burning of the candle per hour
<math> 4a = L</math> ;; total burning time from above

<math> a = L/4</math>

<math> 2b = L+1</math>

<math> b = (L+1)/2</math>

Using the above equations and substituting back into the original we get:

<math>L-2.5(L/4)=(L+1)-4(L+1)/2 </math>

<math>L=8/11</math>

Length of Candle B (longer candle) is 19/11 cm and the length of the Candle A (shorter candle) is 8/11 cm.

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-11T06:49:18Z

AliHussein:

Group members:
* Kazi Ahmed
* Edith Fan
* Maria Fayloga
* Ali Abdi Hussein
* Ellen Tsang | ellentsang.nl@hotmail.com

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-11T06:45:13Z

AliHussein:

Group members:
* Kazi Ahmed
* Edith Fan
* Maria Fayloga
* Ali Abdi Hussein
* Ellen Tsang | ellentsang.nl@hotmail.com

hi guyz!
I'm out of the town and quite busy. the third part of the assignment is a group project and its based on conceptual skills so plz let one of u do it. I recommend Ellen!

Ali

Course:MATH110/Archive/2010-2011/003/Groups/Group 09

2010-10-11T06:43:56Z

AliHussein:

User:AliHussein

2010-09-20T01:59:32Z

AliHussein: Created page with 'I'm Ali, I was born in Kismayu,Somalia. I'm art student at the ubc. i wanna study economics and political science honours.'

I'm Ali,

I was born in Kismayu,Somalia. I'm art student at the ubc. i wanna study economics and political science honours.