# Science:Math Exam Resources/Courses/MATH110/December 2015/Question 05 (c)/Solution 1

According to the Hint, it is enough to check the sign of ${\displaystyle v=h'}$ at ${\displaystyle t={\frac {\pi }{6}}}$.
From the part (b), we have ${\displaystyle v\left({\frac {\pi }{6}}\right)=0.1>0}$, and therefore, ${\displaystyle h}$ is increasing at ${\displaystyle t={\frac {\pi }{6}}}$.
Answer : ${\displaystyle \color {blue}moving\ up}$