A = ( a 1 / 2 − 1 / 2 b ) , {\displaystyle A={\begin{pmatrix}a&1/2\\-1/2&b\end{pmatrix}},}
find values a {\displaystyle a} and b {\displaystyle b} such that A − 1 = A T {\displaystyle A^{-1}=A^{T}} . Note: one set of such values is sufficient.