Science:Math Exam Resources/Courses/MATH152/April 2016/Question B 01 (c)
• QA 1 • QA 2 • QA 3 • QA 4 • QA 5 • QA 6 • QA 7 • QA 8 • QA 9 • QA 10 • QA 11 • QA 12 • QA 13 • QA 14 • QA 15 • QA 16 • QA 17 • QA 18 • QA 19 • QA 20 • QA 21 • QA 22 • QA 23 • QA 24 • QA 25 • QA 26 • QA 27 • QA 28 • QA 29 • QA 30 • QB 1(a) • QB 1(b) • QB 1(c) • QB 1(d) • QB 2(a) • QB 2(b) • QB 2(c) • QB 2(d) • QB 3(a) • QB 3(b) • QB 3(c) • QB 4(a) • QB 4(b) • QB 4(c) • QB 4(d) • QB 5(a) • QB 5(b) • QB 5(c) • QB 5(d) • QB 6(a) • QB 6(b) • QB 6(c) •
Question B 01 (c) 

Consider the lines (c) Do the lines and intersect? If so, find the intersection point. If not, explain. 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hint below. Consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! 
Hint 

A point lies on if and only if for some . Similarly, iff for some . 
Checking a solution serves two purposes: helping you if, after having used the hint, you still are stuck on the problem; or if you have solved the problem and would like to check your work.

Solution 

Found a typo? Is this solution unclear? Let us know here.
Please rate my easiness! It's quick and helps everyone guide their studies. If a point is a intersection point of the lines and , then and . In other words, for some and . By expanding the second equality, we have The first component implies that and we plug this into the equation from the second component; So, we have and . However, these values of and doesn't satisfy the equation from the third component; This means there's no and to make hold. In other words, there's no intersection point. 
Please rate how easy you found this problem:
Nobody voted on this yet Hard Easy 