From the graph of f {\displaystyle f} in part (a), we can easily see that f ( 0 ) = 1 {\displaystyle f(0)=1} , but lim x → 0 − f ( x ) = 1 ≠ 0 = lim x → 0 + f ( x ) {\displaystyle \lim _{x\to 0-}f(x)=1\neq 0=\lim _{x\to 0+}f(x)} .
Therefore, the given function is not continuous, because the limit lim x → 0 f ( x ) {\displaystyle \lim _{x\to 0}f(x)} doesn't exist.
Answer: ( i i ) {\displaystyle \color {blue}(ii)}
