Find the absolute minimum y = x x − 3 3 = x ( x − 3 ) 1 / 3 {\displaystyle y=x{\sqrt[{3}]{x-3}}=x(x-3)^{1/3}} on the interval [ 0 , 4 ] {\displaystyle \left[0,4\right]}
![{\displaystyle y=x{\sqrt[{3}]{x-3}}=x(x-3)^{1/3}}](https://wiki.ubc.ca/api/rest_v1/media/math/render/svg/4dd915d7f459127712f4ae27d4a54dafc6c8e20b)
![{\displaystyle \left[0,4\right]}](https://wiki.ubc.ca/api/rest_v1/media/math/render/svg/dd04af5bb35776de469be99e538a5cc93c2c90bb)