Science:Math Exam Resources/Courses/MATH103/April 2016/Question 06 (a) (i)/Hint 1

Given the base growth rate $r_{\mathrm {max} }$ and carrying capacity $K,$ the logistic differential equation is given by

${\frac {dN}{dt}}=r_{\mathrm {max} }N\left(1-{\frac {N}{K}}\right).$