Science:Math Exam Resources/Courses/MATH101/April 2011/Question 05 (b)
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Question 05 (b) 

BirdBath and Beyond Incorporated is famous for its Quetzal attracting birdfeeder solution made from water, honey and canesugar. To make their solution, both honey and a canesugar solution are poured into a 200 L mixing tank. The honey is poured in at a rate of 1 L per minute while the sugar solution is poured in at 9 L per minute. Note that 1 L of honey contains 1 kg of sugar, while the canesugar solution contains 100g of sugar per L. Unfortunately today there is a problem with the mixing tank. It was thoroughly cleaned and is initially filled with pure water, but main valve was broken and the water cannot be drained. When the mixing process is started, the honey and sugarsolutions are poured into the tank, and the excess fluid flows out of an emergency valve at 10 L per minute and onto the floor. You should assume that the solutions mix immediately and thoroughly in the tank. (b) How much sugar is in the tank after time t? 
Make sure you understand the problem fully: What is the question asking you to do? Are there specific conditions or constraints that you should take note of? How will you know if your answer is correct from your work only? Can you rephrase the question in your own words in a way that makes sense to you? 
If you are stuck, check the hints below. Read the first one and consider it for a while. Does it give you a new idea on how to approach the problem? If so, try it! If after a while you are still stuck, go for the next hint. 
Hint 1 

Solve the differential equation found in part (a). 
Hint 2 

To solve the differential equation, separate the variables. 
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Solution 

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Please rate my easiness! It's fun and helps everyone guide their studies. Recall that the differential equation is given by We use separation of variables and bring all terms with S to the left hand side, and all terms involving t to the right hand side. So we multiply both sides with and divide by :
Solving the above for S yields with a different constant . Now we use the initial condition S(0) = 0 to solve for C_{2}: hence C_{2} = 1.9 and therefore the final answer is 
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